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aalyn [17]
3 years ago
13

2(x+5)-3=-(2x+1)+1 What is the solution for x???

Mathematics
1 answer:
netineya [11]3 years ago
8 0
Hi there,

2 (x +5) - 3 = -(2x + 1) + 1
2x + 10 - 3 = -2x - 1 + 1
2x + 10 - 3 = -2 - 1 + 1
2x + 7 = -2x
2x + 2x = -7
4x = -7

Hence, X=   -7/4  

Hope this helps :)

Brainliest please
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Quadrilateral BECK is known to be a rhombus. Two of the vertices are B(3,5) and C(7,-3).
Zanzabum

Answer:

a. The slope of EK is \frac{1}{2}

b. The equation of line EK is y = \frac{1}{2} x -  \frac{3}{2}

Step-by-step explanation:

The form of the equation of a line is y = m x + b, where

  • m is the slope of the line
  • b is the y-intercept

The rule of the slope is m = \frac{y2-y1}{x2-x1} , where

  • (x1, y1) and (x2, y2) are two points on the line
  • The rule of the mid-point is (\frac{x1+x2}{2},\frac{y1+y2}{2})

∵ BECK is a rhombus

∵ The diagonal is the line that joins two opposite vertices

∵ B and C are opposite vertices in the rhombus

∵ E and K are opposite vertices in the rhombus

∴ BC and EK are the diagonals of the rhombus BECK

∵ The diagonals of the rhombus are ⊥ and bisect each other

∴ EK is ⊥ bisector to BC

→ Let us find the slope and the mid-point of BC

∵ B = (3, 5) and C = (7, -3)

∴ x1 = 3 and y1 = 5

∴ x2 = 7 and y2 = -3

→ Substitute them in the rule of the slope above to find it

∵ m = \frac{-3-5}{7-3} = \frac{-8}{4} = -2

∴ m = -2

∴ The slope of BC = -2

→ To find the slope of EK reciprocal the slope of BC and change its sign

∴ m⊥ = \frac{1}{2}

∴ The slope of EK = \frac{1}{2}

a. The slope of EK is \frac{1}{2}

→ Substitute the value of the slope in the form of the equation above

∵ y = \frac{1}{2} x + b

→ To find b substitute x and y in the equation by the coordinates

   of a point on the line

∵ The mid-point of BC is the mid-point of EK

∵ The mid-point of BC = (\frac{3+7}{2},\frac{5+-3}{2}) = (\frac{10}{2},\frac{2}{2}) = (5, 1)

∴ The mid-point of EK = (5, 1)

→ Substitute x by 5 and y by 2 in the equation

∵ 1 =  \frac{1}{2}(5) + b

∴ 1 =  \frac{5}{2} + b

→ Subtract  \frac{5}{2} from both sides

∴  -\frac{3}{2} = b

→ Substitute the value of b in the equation

∵ y = \frac{1}{2} x + -\frac{3}{2}

∴ y = \frac{1}{2} x -  \frac{3}{2}

b. The equation of line EK is y = \frac{1}{2} x -  \frac{3}{2}

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