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3 years ago

11

A city planner is rerouting traffic in order to work on a stretch of road. The equation of the path of the old route can be desc

ribed as y = two fifthsx − 4. What should the equation of the new route be if it is to be perpendicular to the old route and will go through point (P, Q)? y − Q = negative five halves(x − P) y − Q = two fifths(x − P) y − P = negative five halvesx − Q) y − P = two fifths(x − Q)

2 answers:

neonofarm [45]3 years ago

7 0

Answer:

<em>y - P = -5/2 (x - Q)</em>

Step-by-step explanation:

on flvs geometry module 4 test, this is correct!

Lana71 [14]3 years ago

3 0

Answer:

y - Q = 2/5 (x - P)

Step-by-step explanation:

because parallel lines always have the same slope

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Determine the equation of the line that passes through the points (-1 , 10) and (2,4)

docker41 [41]

Given:

The two points are (-1,10) and (2,4).

To find:

The equation of line which passes though the given points.

Solution:

If a line passes through two points, then the equation of line is

$y-y_1=\dfrac{y_2-y_1}{x_2-x_1}(x-x_1)$

The line passes through (-1,10) and (2,4). So, the equation of line is

$y-10=\dfrac{4-10}{2-(-1)}(x-(-1))$

$y-10=\dfrac{-6}{2+1}(x+1)$

$y-10=\dfrac{-6}{3}(x+1)$

$y-10=-2(x+1)$

Using distributive property, we get

$y-10=-2x-2$

Adding 10 both sides, we get

$y=-2x-2+10$

$y=-2x+8$

Therefore, the required equation of line is $y=-2x+8$ .

5 0

3 years ago

Tell whether the triangle with the given side lengths is a right triangle.<br> 24, 70, 75

alexgriva [62]

Answer:

Not a right triangle.

Step-by-step explanation:

We can tell if it's a right triangle or not by using the Pythagorean Theorem.

The largest value is always the hypotenuse (c).

a² + b² = c²

24² + 70² = 75²

576 + 4900 = 5625

5476 ≠ 5625

The values do not equal one another. Therefore, this triangle is NOT a right triangle.

6 0

3 years ago

At a unit price of $900, the quantity demanded of a certain commodity is 75 pounds. If the unit price increases to $956, the qua

Nady [450]

Answer:

1) The demand equation is $x=-0.25p+300$

2) The price when no consumers willing to buy this commodity is $1200.

3) The quantity of the commodity would consumers take if it was free is 300 pounds.

Step-by-step explanation:

Given : At a unit price of $900, the quantity demanded of a certain commodity is 75 pounds. If the unit price increases to $956, the quantity demanded decreases by 14 pounds.

To find :

1) The demand equation ?

2) At what price are no consumers willing to buy this commodity?

3) According to the above model, how many pounds of this commodity would consumers take if it was free?

Solution :

1) According to question,

p is the unit price and x is the quantity demanded for this commodity in pounds.

Let, $p_1=\$900$ and $x_1=75\text{ pounds}$

and $p_2=\$956$ and $x_2=75-14=61\text{ pounds}$

To find the demand equation we apply two point slope form,

$(x - x_1)=\frac{(x_2-x_1)}{(p_2-p_1)}\times(p-p_1)$

Substitute the values,

$(x - 75)=\frac{61-75}{956-900}\times(p-900)$

$(x - 75)=\frac{-14}{56}\times(p-900)$

$(x - 75)=\frac{-1}{4}\times(p-900)$

$x-75=-\frac{1}{4}p+225$

$x=-\frac{1}{4}p+300$

$x=-0.25p+300$

The demand equation is $x=-0.25p+300$

2) For no consumers,

Substitute x=0 in demand equation,

$0=-0.25p+300$

$0.25p=300$

$p=\frac{300}{0.25}$

$p=1200$

The price when no consumers willing to buy this commodity is $1200.

3) For free,

Substitute p=0 in demand equation,

$x=-0.25(0)+300$

$x=300$

The quantity of the commodity would consumers take if it was free is 300 pounds.

3 0

3 years ago

In a class of 300 students ,20% are girls how many boys are there?

emmainna [20.7K]

Answer:

240 students are boys

Step-by-step explanation:

20% of 300 = 60

300 - 60 = 240

3 0

3 years ago

Read 2 more answers

If L is the line through the point (-3,5) having a slope of (2/3) complete the equation of L

Artist 52 [7]

Y = mx + b
slope(m) = 2/3
(-3,5)...x = -3 and y = 5
now sub and find b, the y int
5 = 2/3(-3) + b
5 = -2 + b
5 + 2 = b
7 = b

so ur equation is : y = 2/3x + 7

4 0

3 years ago