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Alina [70]
2 years ago
12

Sanford the elf has been asked to choose toys for a child who wants a baby doll, a jigsaw puzzle, and a stuffed dog. He looks on

the shelves in the toy shop and sees 11 different baby dolls, 6 different jigsaw puzzles, and 3 different stuffed dogs. In how many ways can he choose a baby doll, jigsaw puzzle, and stuffed dog for the child?
Mathematics
1 answer:
zmey [24]2 years ago
5 0

Answer: There are 198 different combinations.

Step-by-step explanation:

To solve this type of problem, first, we need to identify the selections.

We have 3 selections.

Baby doll, Jigsaw puzzle, and a stuffed dog.

Now, we need to count the numbers of options for each case:

Baby doll: 11 options.

Jigsaw Puzzle: 6 options.

Stuffed dog: 3 options.

To find the total number of different combinations, we need to multiply all the numbers of options together, this is:

Combinations = 11*6*3 = 198

There are 198 different combinations.

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An average male Asian elephant grows to about three meters at the shoulders. What is the average height in centimeters?
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Answer:

300 centimeters

Step-by-step explanation:

1 meter is equal to 100 cm so 3 x 100 = 300

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RSB [31]

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False

Step-by-step explanation:

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3 years ago
If f(1) = 10 and f(n) = f(n = 1) – 4 then find the value of f(5).
svetoff [14.1K]

Given:

f(1)=10 and f(n)=f(n-1)-4.

To find:

The value of f(5).

Solution:

We have,

f(n)=f(n-1)-4

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f(2)=f(2-1)-4

f(2)=f(1)-4

f(2)=10-4

f(2)=6

For n=3,

f(3)=f(3-1)-4

f(3)=f(2)-4

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f(5)=-6

Therefore, the value of f(5) is -6.

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