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timama [110]
3 years ago
8

A rectangle has a diagonal of 277 centimeters and a length of 252cm. How long is the width?

Mathematics
2 answers:
Mamont248 [21]3 years ago
8 0

Answer:

115

Step-by-step explanation:

Crank3 years ago
7 0

Answer:

width = 115 cm

Step-by-step explanation:

width² = 277² - 252²

width² = 76729 - 63504 = 13225

width = 115 cm

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Evaluate the expression for the given value of the variable <br> 3a+4b; a= -6, b=-5
Dimas [21]
3 x -6 + 4 x -5
= -18+ -20
= -38
5 0
3 years ago
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siniylev [52]

Answer:

<h2>no solution</h2>

Step-by-step explanation:

-x^2-9\geq0\qquad\text{change the signs}\\\\x^2+9\leq0\\\\\text{the parabola}\ x^2\ \text{is op}\text{en up and shifted 9 units up. Therefore is whole}\\\text{over the x-axis (only positive values)}.\\\\\bold{CONCLUSION}:\\\\\bold{no\ solution}

5 0
3 years ago
A regular pentagon ABCDE is shown <br><br><br> Work out the size of X
nikdorinn [45]
The sum of the angles in a pentagon is 540°.

This means that each angle is 108°.

Inside you pentagon, a triangle is drawn. This triangle is isosceles, because the corners are on the points of the regular pentagon. You know that angle C is 108°.

Angles in a triangle add up to 180°.

B and D will be the same size as this is isosceles.

180°-108° = 72°

This is B and D. You only need one of these, so you divide by 2.

The answer is 36°.

Hope this helps :)
7 0
3 years ago
Read 2 more answers
A 3pack of boxes of juice costs 1.09. A 12 pack of boxes cost 4.49. A case of 24 boxes costs 8.78. Which is the best buy?Explain
Leona [35]
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5 0
3 years ago
As voters exit the polls, you ask a representative random sample of voters if they voted for a proposition. If the true percenta
tresset_1 [31]

Answer:

The probability is 0.057797

Step-by-step explanation:

Consider the provided information.

It is given that true percentage of voters who vote for the proposition is 63%,

Let p is probability of success.

According to the binomial distribution:

P(x;p,n)=^nC_x(p)^x(1-p)^{(n-x)}

Substitute n=7, p=0.63 and x=2 in the above formula.

P(x;p,n)=^7C_2(0.63)^2(1-0.63)^{(7-2)}

P(x;p,n)=\frac{7!}{2!5!}(0.3969)(0.37)^{5}\\P(x;p,n)=21(0.3969)(0.37)^{5}\\P(x;p,n)=0.0577974947199\\P(x;p,n)\approx0.057797

Hence, the probability is 0.057797

8 0
3 years ago
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