If you need an equation it is -3.4x=21.5
You simply divide both sides by -3.4 to get x=-6.32
if that's not right then just get on a calculator and calculate by doing what I said to divide
Answer:
Part 1)
Part 2)
a)
b)
c)
Step-by-step explanation:
<u><em>The complete question in the attached figure</em></u>
Part 1) Write an expression for the perimeter of the shape
we know that
The figure is composed by a larger square, a rectangle and a smaller square
1) The area of the larger square is given
so
The length and the width of the larger square is x units
2) The area of the rectangle is given
so
The length of the rectangle is x units and the width is 1 unit
3) The length and the width of the smaller square is x units
see the attached figure N 2 to better understand the problem
Find out the perimeter
The perimeter is the sum of all the sides.
so
Part 2) Find the perimeter for each of the given values of x.
a) For x=7 units
Substitute the value of x in the expression of the perimeter
b) For x=5.5 units
Substitute the value of x in the expression of the perimeter
b) For x=7/3 units
Substitute the value of x in the expression of the perimeter
For the sake of example, let's multiply the two numbers
and
together. Altogether, we have:
Rearranging the expression, we can group the exponents and coefficients together:
Multiplying each out, we notice that since
and
have the same base (10), multiplying them has the effect of adding their exponents, which leaves us with:
The takeaway here is that multiplying two numbers in scientific notation together has the effect of multiplying its coefficients and <em>adding</em> its exponents.
There is no one answer (ordered pair) to this equation and the answer is found by graphing or trying out different values for each variable. Anyway, here are some solutions; (1,0), (4,1), (0,-1/3).
Width would have to be a quadratic
Use long division to find the other factor of the cubic polynomial P (x).
P (x) factors in case it is reducible over R[x]
if it weren't then P (x) mod R [x] would be a field
otherwise you could use the Eisenstein Criterion.