The result of simplifying the expression (x²/x⁻¹¹)¹/₃ using the exponent rules is ![\sqrt[3]{}](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B%7D)
(x¹³)
To solve this exercise we have to resolve algebraic operations following the exponent rules.
(x²/x⁻¹¹)¹/₃
Using the quotient rule that indicates that: the exponent result will be the subtraction of these exponents, we have:
(x⁽²⁻⁽⁻¹¹⁾)¹/₃
(x⁽²⁺¹¹⁾)¹/₃
(x¹³)¹/₃
Using the power of a power rule that indicates that: the exponent result will be the multiplication of these powers, we have:
x⁽¹³*¹/₃⁾
x⁽¹³/₃⁾
As we have a fractional exponent, you must convert the exponent to root:
(x¹³)
<h3>What is an exponent?</h3>
In mathematics an exponent is the number of time that a number, called (base) is multiplied by itself. It is also called, power or index.
Example: 3² = 3*3 = 9
Learn more about exponent at: brainly.com/question/847241
#SPJ4
Answer:
D) 4 1/2
Step-by-step explanation:
Hope that helps :)
Drawing this square and then drawing in the four radii from the center of the cirble to each of the vertices of the square results in the construction of four triangular areas whose hypotenuse is 3 sqrt(2). Draw this to verify this statement. Note that the height of each such triangular area is (3 sqrt(2))/2.
So now we have the base and height of one of the triangular sections.
The area of a triangle is A = (1/2) (base) (height). Subst. the values discussed above, A = (1/2) (3 sqrt(2) ) (3/2) sqrt(2). Show that this boils down to A = 9/2.
You could also use the fact that the area of a square is (length of one side)^2, and then take (1/4) of this area to obtain the area of ONE triangular section. Doing the problem this way, we get (1/4) (3 sqrt(2) )^2. Thus,
A = (1/4) (9 * 2) = (9/2). Same answer as before.
6y+y(4)
7y(4)
y=4/7
Youre welcome
