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Valentin [98]
3 years ago
6

Which describes the slope of this line?

Mathematics
2 answers:
Vedmedyk [2.9K]3 years ago
5 0
Zero slope because no rise so the rise is 0
jolli1 [7]3 years ago
4 0

Answer:

B. Zero Slope

Step-by-step explanation:

The slope is in a horizontal line so it is undefined.

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Find the equation of the line that passes through the point left (-9,12) and is perpendicular to the line y=3/2x-1/2. Write the
ohaa [14]

Answer:

The answer to your question is: y = -2/3 x + 18

Step-by-step explanation:

Data

Point = (-9, 12)

line   y = 3/2x -1/2     perpendicular

Process

The line must be perpendicular to the line given. Then,

slope is the line given = 3/2, we change it because the lines must be perpendicular ,

New slope         M =  -2/3

New line       y-y1 = m(x - x1)

                     y - 12 = -2/3 (x + 9)             Substitution

                   3( y - 12) = -2(x + 9)

                   3y - 36 = -2x - 18                 Simplify

                   3y = -2x - 18 + 36

                   3y = -2x + 18

                      y = -2/3 x+ 18                      Result

8 0
3 years ago
Solve for r. 12 = r - (34 - 2) Show your work!
djverab [1.8K]
The answer would be -20
3 0
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Which equation represents the polar form of x² + (y + 4)² = 16?
Paraphin [41]

x^2+y^2=r^2\hspace{5em}x=r\cos(\theta )\hspace{5em}y=r\sin(\theta ) \\\\[-0.35em] ~\dotfill\\\\ x^2+(y+4)^2=16\implies x^2+\stackrel{binomial~expansion}{y^2+8y+16}=16 \\\\\\ \underset{x^2+y^2}{r^2} + 8(~\underset{8y}{r\sin(\theta )}~)=16-16\implies r^2+8r\sin(\theta)=0 \\\\\\ r^2=-8r\sin(\theta )\implies \cfrac{r^2}{r}=-8\sin(\theta )\implies r=-8\sin(\theta )

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May someone help, please ? Thank you ♥️
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My final answer is (C) because for the side lenghts to be a right triangle, the values of the first and second terms should be equal to the third (a^2 and b^2 =c^2) hope that helped (:
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3 years ago
Seven times the difference of a number and 1
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7(x-1)

You need to provide an "equals" in order to find what x equals

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