Given :
Area of rectangle.
To Find :
The dimensions of a rectangle (in m) with area 1,728 m2 whose perimeter is as small as possible.
Solution :
Let, the dimensions of rectangle is x and y.
Area, A = xy.
x = A/y. ....1)
Perimeter, P = 2( x + y )
Putting value of x in above equation, we get :
For minimum P,
SO, it is a square.
Therefore, the dimensions are 
.24\sqrt{3}
Hence, this is the required solution.
－81＝3(5－4r)
27＝－(5－4r)
27＝－5＋4r
－4r＝－5－27
－4r＝－32
r＝8
Hope my answer helped u :)
The answer is 35 bc it has pointed on the dot
Answer:
CD = 10√3
Step-by-step explanation:
First of all, you need to understand the terms. The <em>incenter</em> is the center of an inscribed circle. Such a circle is tangent to all three sides of the triangle at points B, D, and F. The distances BG, DG, and FG are each the radius of the circle.
The diagram shows FG = 22, so that is also the measure of DG. This gives you two of the three sides of right triangle CDG, so you know enough to apply the Pythagorean theorem.
CG^2 = CD^2 + DG^2
28^2 = CD^2 + 22^2
300 = CD^2 . . . . . . . . subtract 22^2
10√3 = CD . . . . . . . . . take the positive square root
The measure of CD is 10√3.
_____
The process is to understand the geometric relationships and what they mean regarding the algebraic relationships. Then you use the algebraic relationships to write equations that let you find the unknowns you seek.
Its formula Is h^2=b^2+c^2
and it involves the perpendicular, the base and the hypotenuse of a right triangle only.
Usually in questions, one of the value is not given and we have to solve using the theorem to get the last value
