Answer:
3
Step-by-step explanation:
The force is 1.6N and the distance between them is 1.3 meters
<h3>The force between them</h3>
An inverse variation from force to the square of distance is represented s:
k = Fd^2
Where k represents the variation constant
When F = 10, d = 2.
So, we have:
k = 10 * 2^2
k = 40
Substitute k = 40 in k = Fd^2
Fd^2 = 40
When d = 5, we have:
F * 5^2 = 40
This gives
25F = 40
Divide by 25
F = 1.6
Hence, the force is 1.6N
<h3>The distance between them</h3>
In (a), we have:
Fd^2 = 40
When F = 25, we have:
25 * d^2 = 40
This gives
25d^2 = 40
Divide by 25
d^2 = 1.6
Take the square root of both sides
d = 1.3
Hence, the distance between them is 1.3 meters
Read more about variation at:
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100% of 36 ft= 36 ft
50% of 36 ft= 18 ft
5% of 36 ft = 1.8 ft
50%-5% or 18-1.8 ft gives you 16.2 ft
Answer:
3, 12, 21
Step-by-step explanation:
The change is +9
Answer:
1) Pr(all three) = 0.064
2) Pr(none) = 0.216
3) Independent event
Step-by-step explanation:
Let Probability of homes constructed in the Quail Creek area with a security system = Pr (security)
Where Pr = probability
This is a binomial distribution problem. There ate only two outcomes in this distribution: a success and a failure
Where p = success, q = failure
For n trials,
Pr(X = x) = n!/[(n-x)!x!] × p^x × q^(n-x)
Pr (security) = 40% = 0.4
p = 0.4
q = 1-p = 1-0.4 = 0.6
Numbers selected at random = n = 3
See attachment for more details on the workings.
1) Probability all three of the selected homes have a security system = Pr(all three)
Pr(all three) = 1× (0.4)³ (0.6)^0 = 0.4³
= 0.4×0.4×0.4
Pr(all three) = 0.064
2) Probability none of the three selected homes have a security system
= Pr(none)
Pr(none) = 1 × (0.4)^0 × (0.6)³
= 0.6³ = 0.6×0.6×0.6
Pr(none) = 0.216
3) The events were assumed to be independent as the selection of one house doesn't affect the outcome of the selection of another.