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Phoenix [80]
3 years ago
7

Question 7 #7) What value of m makes the equation true? 3(8 – m) = 5m – 40

Mathematics
2 answers:
Anastaziya [24]3 years ago
7 0

Answer:

8

Step-by-step explanation:

3(8-m)=5m-40

you first distribute 3 through the parenthesis

24-3m=5m-40

Move the variable to the left and change sign

24-3m-5m=-40

now move the constant to the right

-3m-5m=-40-24

collect like terms

-8m=-40-24

-8m=-64

Divide both sides by -8 and negative divide negative number becomes positive

so m = 8

Katarina [22]3 years ago
5 0

so I put your equation in cymath. feel free to use it whenever you need help. it really do comes in handy.

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Riley rakes 1/6 of a lawn in 2/3 hour. How many lawns can Riley rake per hour?
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Manufacture of a certain component requires three different machining operations. Machining time for each operation has a normal
tigry1 [53]

Answer:

0.0314 = 3.14% probability that it takes at most 1 hour of machining time to produce a randomly selected component

Step-by-step explanation:

Normal Probability Distribution:

Problems of normal distributions can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the z-score of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.

Sum of normal variables:

When normal variables are added, the mean is the sum of the means while the standard deviation is the square root of the sum of the variances.

The mean values are 20, 15, and 30 min, respectively:

This means that \mu = 20 + 15 + 30 = 65

The standard deviations are 1, 2, and 1.5 min, respectively.

This means that \sigma = \sqrt{1^2 + 2^2 + 1.5^2} = 2.6926

What is the probability that it takes at most 1 hour of machining time to produce a randomly selected component?

Mean and standard deviation are in minutes, so this is the pvalue of Z when X = 60.

Z = \frac{X - \mu}{\sigma}

Z = \frac{60 - 65}{2.6926}

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Z = -1.86 has a pvalue of 0.0314

0.0314 = 3.14% probability that it takes at most 1 hour of machining time to produce a randomly selected component

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