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Contact [7]
3 years ago
13

In your opinion, how do you think we will be able to use the change of base rule?

Mathematics
1 answer:
Zarrin [17]3 years ago
4 0

Answer: Its asking for an opinion answer in your own words

Step-by-step explanation:

You might be interested in
Q1- Write 46 821 correct to the nearest 100
noname [10]

Answer:

46800

Step-by-step explanation:

46821 nearest 100s

look for the tens it is less than 5 so its 800 and the numbers written before the 100s would remain the same

8 0
3 years ago
Is -6.333 greater less equal to -6.375
Leviafan [203]
6.375 is greater than 6.333
3 0
3 years ago
Read 2 more answers
4x27-3+5x2=......................
kolbaska11 [484]

Answer:

115

Step-by-step explanation:

8 0
3 years ago
simplify, 6+3-3-3-3-3-21-5-5234-534-5-4-4-3-43-3-443--4-4-4-4--4-4-4-4-4-4-4--44-4--4-4-4=5647765865886*556386588668*56586856853
Nataly [62]

Answer:

−6294≠Infinity

Step-by-step explanation:

−6294≠Infinity

5 0
3 years ago
Use the mid-point rule with n = 4 to approximate the area of the region bounded by y = x3 and y = x. (10 points)
USPshnik [31]
See the graph attached.

The midpoint rule states that you can calculate the area under a curve by using the formula:
M_{n} = \frac{b - a}{2} [ f(\frac{x_{0} + x_{1} }{2}) +  f(\frac{x_{1} + x_{2} }{2}) + ... +  f(\frac{x_{n-1} + x_{n} }{2})]

In your case:
a = 0
b = 1
n = 4
x₀ = 0
x₁ = 1/4
x₂ = 1/2
x₃ = 3/4
x₄ = 1

Therefore, you'll have:
M_{4} = \frac{1 - 0}{4} [ f(\frac{0 +  \frac{1}{4} }{2}) +  f(\frac{ \frac{1}{4} + \frac{1}{2} }{2}) +  f(\frac{\frac{1}{2} + \frac{3}{4} }{2}) + f(\frac{\frac{3}{4} + 1} {2})]
M_{4} = \frac{1}{4} [ f(\frac{1}{8}) +  f(\frac{3}{8}) +  f(\frac{5}{8}) + f(\frac{7}{8})]

Now, to evaluate your f(x), you need to look at the graph and notice that:
f(x) = x - x³

Therefore:
M_{4} = \frac{1}{4} [(\frac{1}{8} - (\frac{1}{8})^{3}) + (\frac{3}{8} - (\frac{3}{8})^{3}) + (\frac{5}{8} - (\frac{5}{8})^{3}) + (\frac{7}{8} - (\frac{7}{8})^{3})]

M_{4} = \frac{1}{4} [(\frac{1}{8} - \frac{1}{512}) + (\frac{3}{8} - \frac{27}{512}) + (\frac{5}{8} - \frac{125}{512}) + (\frac{7}{8} - \frac{343}{512})]

M₄ = 1/4 · (2 - 478/512)
     = 0.2666

Hence, the <span>area of the region bounded by y = x³ and y = x</span> is approximately 0.267 square units.

6 0
3 years ago
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