Na₂CO₃(s) → 2Na⁺(aq) + CO₃²⁻(aq)
The sodium carbonate formed from a strong base and a weak acid. Hydrolysis is subjected to the anion of a weak acid.
CO₃²⁻ + H₂O ⇄ HCO₃⁻ + OH⁻
HCO₃⁻ + H₂O ⇄ H₂CO₃ + OH⁻
pH>7 alkaline solution
2Na⁺ + CO₃²⁻ + 2H₂O ⇄ 2Na⁺ + 2OH⁻ + H₂CO₃
Answer:
C2H4O2 + 2O2 —> 2CO2 + 2H20
The coefficients are 1, 2, 2, 2
Explanation:
C2H4O2 + O2 —> CO2 + H20
To balance the above, do the following
Since there are 2 carbon on the left, put 2 in front of CO2, we have
C2H4O2 + O2 —> 2CO2 + H20
We have 4 hydrogen on the left, to balance it put 2 in front of H2O i.e
C2H4O2 + O2 —> 2CO2 + 2H20
Now, we have a total of 6 oxygen on the right side. To balance it, put 2 in front of O2:
C2H4O2 + 2O2 —> 2CO2 + 2H20
The coefficients are 1, 2, 2, 2
Answer:
334.4J
Explanation:
Q = mass×specific heat capacity (final temperature - initial temperature) = 100 × 4.18 (23.40 - 22.60) = 100 × 4.18× 0.80 = 334.4J