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Aleksandr [31]
3 years ago
11

Acid spills are often neutralized with sodium carbonate. For example

Chemistry
1 answer:
Vsevolod [243]3 years ago
6 0

Answer:

4770 grams of sodium carbonate

Explanation:

The reaction that takes place between sodium carbonate and sulfuric acid is:

  • Na₂CO₃ (s) + H₂SO₄ (aq) → Na₂SO₄ (aq) + CO₂(g) + H₂O (l)

First we <u>calculate how many H₂SO₄ moles reacted</u>, using the <em>given concentration and volume of solution</em>:

moles = Molarity * Liters

  • moles = 18.0 M * 2.50 L = 45 mol H₂SO₄

Then we <u>convert H₂SO₄ moles into NaCO₂ moles</u>, using the <em>stoichiometric coefficients</em>:  

  • 45 mol H₂SO₄ * \frac{1molNa_2CO_3}{1molH_2SO_4} = 45 mol NaCO₂

Finally we <u>convert 45 NaCO₂ moles into grams</u>, using its <em>molar mass</em>:

  • 45 mol NaCO₂ * 106 g/mol = 4770 g

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