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Flura [38]
3 years ago
13

Suppose the cost C(x), to build a football stadium of x thousand square feet is approximated by C(x) = 7,250,000/ x + 60 . How m

any square feet was the stadium if the cost of the stadium was $8,000?
Mathematics
1 answer:
Luba_88 [7]3 years ago
7 0

Answer:

Step-by-step explanation:

Suppose the cost C(x), to build a football stadium of x thousand square feet is approximated by C(x) = 7,250,000/x + 60. Given the function, we can substitute values for x to determine the cost of a particular size of stadium or we can substitute values for C(x) to determine the number of square feet.

if the cost of the stadium was $8,000, the, we would determine the size of the stadium, x by substituting x $8,000 for C(x). It becomes

8000 = 7250,000/x + 60

8000 - 60 = 7250000/x

7940 = 7250000/x

7940x = 7250000

x = 7250000/ 7940

x = 913 ft^2

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Answer:

\boxed {d = 5}

Step-by-step explanation:

Use the <u>Distance Formula</u> to help you determine the distance between two given points:

d = \sqrt{(x_{2} - x_{1})^{2} + (y_{2} - y_{1})^{2}}

First point: (x_{1}, y_{1})

Second Point: (x_{2}, y_{2})

-Apply the two given points onto the formula:

First point: (1, 4)

Second point: (-2, 0)

d = \sqrt{(-2 - 1)^{2} + (0 - 4)^{2}}

-Solve for the distance:

d = \sqrt{(-2 - 1)^{2} + (0 - 4)^{2}}

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\boxed {d = 5}

Therefore, the distance is 5.

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2 years ago
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Answer:

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