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3 years ago

What is the distance between points S and U if S is 2, 1 and U is 6, 8

Mathematics

2 answers:

sleet_krkn [62]3 years ago

5 0

Answer:

Step-by-step explanation:

S has coordinates (2 , 1) and U has coordinates (6, 8) . Computing the SU vector gives us (4 , 7)

taking the distance formula : sqrt(4^2 +7^2)

= sqrt(65) = 8.1 which is answer C

balandron [24]3 years ago

4 0

The distance formula is:

D = sqrt((x2-x1)^2 + (y2-y1)^2)

D= sqrt ((6-2)^2 + (8-1)^2)

D = sqrt(4^2 + 7^2)

D = sqrt( 16 + 49)

D = sqrt(65)

D = 8.06

Rounded to the beat tenth = 8.1 units.

The answer is C. 8.1 units

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Help i am in need of help fast pls

lutik1710 [3]

The order is C,A,B for this problem

6 0

4 years ago

Given line segment AB, the coordinates of A are (3,-5) and the coordinates midpoint are (5,-1), what are the coordinates for B?

dsp73

Answer:

Step-by-step explanation:

Point P(5, -1) being the midpoint of AB means that $x_P-x_A=x_B-x_P$

$5-3=x_B-5\\\\2+5=x_B\\\\x_B=7$

and $y_P-y_A=y_B-y_P$

$-1-(-5)=y_B-(-1)\\\\-1+5=y_B+1\\\\y_B=3$

6 0

3 years ago

Determine whether each expression is equivalent to 49^2t – 0.5.

vampirchik [111]

Answer:

None of the expression are equivalent to $49^{(2t - 0.5)}$

Step-by-step explanation:

Given

$49^{(2t - 0.5)}$

Required

Find its equivalents

We start by expanding the given expression

$49^{(2t - 0.5)}$

Expand 49

$(7^2)^{(2t - 0.5)}$

$7^2^{(2t - 0.5)}$

Using laws of indices: $(a^m)^n = a^{mn}$

$7^{(2*2t - 2*0.5)}$

$7^{(4t - 1)}$

This implies that; each of the following options A,B and C must be equivalent to $49^{(2t - 0.5)}$ or alternatively, $7^{(4t - 1)}$

A. $\frac{7^{2t}}{49^{0.5}}$

Using law of indices which states;

$a^{mn} = (a^m)^n$

Applying this law to the numerator; we have

$\frac{(7^{2})^{t}}{49^{0.5}}$

Expand expression in bracket

$\frac{(7 * 7)^{t}}{49^{0.5}}$

$\frac{49^{t}}{49^{0.5}}$

Also; Using law of indices which states;

$\frac{a^{m}}{a^n} = a^{m-n}$

$\frac{49^{t}}{49^{0.5}}$ becomes

$49^{t-0.5}}$

This is not equivalent to $49^{(2t - 0.5)}$

B. $\frac{49^{2t}}{7^{0.5}}$

Expand numerator

$\frac{(7*7)^{2t}}{7^{0.5}}$

$\frac{(7^2)^{2t}}{7^{0.5}}$

Using law of indices which states;

$(a^m)^n = a^{mn}$

Applying this law to the numerator; we have

$\frac{7^{2*2t}}{7^{0.5}}$

$\frac{7^{4t}}{7^{0.5}}$

Also; Using law of indices which states;

$\frac{a^{m}}{a^n} = a^{m-n}$

$\frac{7^{4t}}{7^{0.5}}$ = $7^{4t - 0.5}$

This is also not equivalent to $49^{(2t - 0.5)}$

C. $7^{2t}\ *\ 49^{0.5}$

$7^{2t}\ *\ (7^2)^{0.5}$

$7^{2t}\ *\ 7^{2*0.5}$

$7^{2t}\ *\ 7^{1}$

Using law of indices which states;

$a^m*a^n = a^{m+n}$

$7^{2t+ 1}$

This is also not equivalent to $49^{(2t - 0.5)}$

6 0

3 years ago

I NEED HELP IM IN CLASS RN PLEASEE HELP! WILL GIVE BRIANLIEST!

fgiga [73]

Answer:

y=x+12

Step-by-step explanation:

Well the slope is -4/-4 =1

We plug it into the formula, y=mx+b, but m=1

So it is y=1x+b

We know the points, so we plug y and x in which is:

-4=-4*4+b

-4=-16+b

b=12

So the point slope form of that is y=x+12

4 0

4 years ago

What is the x-intercepts of y= -2(x-3)[2]+2?

mrs_skeptik [129]

Answer: (x,y)=(14/4,0)

Step-by-step explanation:

y=-2(x-3)(2)+2

Clear the brackets

y=-2(2x-6)+2

y=-4x+12+2

y=-4x+14

To get the x-intercept y=0

0=-4x+14

4x=14

x=14/4

(x,y)=(14/4,0)

8 0

4 years ago

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