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Lady bird [3.3K]

2 years ago

9

Plz help me

1 answer:

KiRa [710]2 years ago

4 0

Answer:

$\left(-4,-2\right)$ , $\left(4,-2\right)$ , $\left(4,4\right)$ , and $\left(-4,4\r the perimeter and the area of the secret chamber

Step-by-step explanation:

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⚠️HURRYPLEASE⚠️what procedure can be

KIM [24]

Answer:

multiplication

Step-by-step explanation:

540=a/11

you multiply by the reciprocal which would be 11/1

that then gives you 5940=a

4 0

2 years ago

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What is the missing number ?? /6 =25/30

matrenka [14]

Answer:

5

Step-by-step explanation:

$\frac{25}{30}$ ( divide numerator and denominator by 5 ) , then

$\frac{25}{30}$ = $\frac{5}{6}$ ( with missing number ? = 5 )

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Solve 9x + 3 = -33 . PLEASE HELP ME IT WILL MAKE MY DAY

ValentinkaMS [17]

$: \implies \sf 9x + 3 = - 33$

$: \implies \sf 9x = - 33 - 3$

$: \implies \sf 9x = - 36$

$: \implies \sf x = \dfrac{ - 36}{9} = - 4$

$\therefore \sf x = -4$

8 0

2 years ago

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All the info is in the pictures

Hunter-Best [27]

Bearing in mind that an absolute value expression is in effect a piece-wise function with two cases, thus

$\bf |-n|=
\begin{cases}
+(-n)\\
-(-n)
\end{cases}\implies 
\begin{cases}
-n\\
n
\end{cases}
\\\\\\
n|-n|=2n\implies 
\begin{cases}
n-n=2n\implies 0=2n\implies &0=n\\
n+n=2n\implies 2n=2n\impliedby &inconsistent
\end{cases}$

6 0

2 years ago

A point H is 20m away from the foot of a tower on the same horizontal ground. From the point H, the angle of elevation of the po

astra-53 [7]

Answer:

a. See Attachment 1

b. $PT = 12.3\ m$

c. $HT = 31.1\ m$

d. $OH = 28.4\ m$

Step-by-step explanation:

Calculating PT

To calculate PT, we need to get distance OT and OP

Calculating OT;

We have to consider angle 50, distance OH and distance OT

The relationship between these parameters is;

$tan50 = \frac{OT}{20}$

Multiply both sides by 20

$20 * tan50 = \frac{OT}{20} * 20$

$20 * tan50 = OT$

$20 * 1.1918 = OT$

$23.836 = OT$

$OT = 23.836$

Calculating OP;

We have to consider angle 30, distance OH and distance OP

The relationship between these parameters is;

$tan30 = \frac{OP}{20}$

Multiply both sides by 20

$20 * tan30 = \frac{OP}{20} * 20$

$20 * tan30 = OP$

$20 * 0.5774= OP$

$11.548 = OP$

$OP = 11.548$

$PT = OT - OP$

$PT = 23.836 - 11.548$

$PT = 12.288$

$PT = 12.3\ m$ (Approximated)

--------------------------------------------------------

Calculating the distance between H and the top of the tower

This is represented by HT

HT can be calculated using Pythagoras theorem

$HT^2 = OT^2 + OH^2$

Substitute 20 for OH and $OT = 23.836$

$HT^2 = 20^2 + 23.836^2$

$HT^2 = 400 + 568.154896$

$HT^2 = 968.154896$

Take Square Root of both sides

$HT = \sqrt{968.154896}$

$HT = 31.1\ m$ <em>(Approximated)</em>

--------------------------------------------------------

Calculating the position of H

This is represented by OH

See Attachment 2

We have to consider angle 50, distance OH and distance OT

The relationship between these parameters is;

$tan50 = \frac{OH}{OT}$

Multiply both sides by OT

$OT * tan50 = \frac{OH}{OT} * OT$

$OT * tan50 = {OH$

$OT * 1.1918 = OH$

Substitute $OT = 23.836$

$23.836 * 1.1918 = OH$

$28.4= OH$

$OH = 28.4\ m$ <em> (Approximated)</em>

5 0

2 years ago