2 years ago

How many moles of sodium cyanide (NaCN) would be needed to

Chemistry

2 answers:

Arturiano [62]2 years ago

6 0

Answer: 8.4

Explantion:

damaskus [11]2 years ago

4 0

Answer:

Explanation:

8.4

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What is the pOH of 0.50 molar H3BO3?

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A. 10.25

Explanation:

Pkb =4.77

So pka = 14 - pka = 9.23

$Ka =10^{-pka}$

$H_3 BO_3 (aq)+ H_2 O(l) H_2 BO_3^- (aq)+H_3 O^+ (aq)$

Initial 0.50M 0 0

Change -x +x +x

Equilibrium 0.50M-x +x +x

$Ka =\frac {((x)(x))}{(0.50M-x)}$

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(-x is neglected) so we get

$5.88\times10^{-10}\times0.50=x^2\\\\x^2=2.94\times10^{-10}$

$x=\sqrt{x^2}=1.72\times10^{-5} M=H^3 O^{+}$

$pH=-log[H^3 O^+]\\\\pH=-log[1.72\times10^{-5}]\\\\pH=4.76$

pOH = 14 - pH

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pOH = 9.24 is the answer

Option A - 10.25 is the answer which is close to 9.24

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