Free electrons tend to go from the negatively charged body to the positively charged body
Here we apply the Clausius-Clapeyron equation:
ln(P₁/P₂) = ΔH/R x (1/T₂ - 1/T₁)
The normal vapor pressure is 4.24 kPa (P₁)
The boiling point at this pressure is 293 K (P₂)
The heat of vaporization is 39.9 kJ/mol (ΔH)
We need to find the vapor pressure (P₂) at the given temperature 355.3 K (T₂)
ln(4.24/P₂) = 39.9/0.008314 x (1/355.3 - 1/293)
P₂ = 101.2 kPa
pH of the acetyl choline solution before incubation = 7.65
![[H_{3}O^{+}]=10^{-7.65}=2.24*10^{-8}M](https://tex.z-dn.net/?f=%5BH_%7B3%7DO%5E%7B%2B%7D%5D%3D10%5E%7B-7.65%7D%3D2.24%2A10%5E%7B-8%7DM)
pH of the solution after incubation = 6.87
![[H_{3}O^{+}]=10^{-6.87}=1.35*10^{-7}M](https://tex.z-dn.net/?f=%5BH_%7B3%7DO%5E%7B%2B%7D%5D%3D10%5E%7B-6.87%7D%3D1.35%2A10%5E%7B-7%7DM)
The difference in concentration of hydronium ion before and after incubation
=
-
=
This difference in hydronium ion concentration can be attributed to the increase in the concentration of acetic acid, which is formed when acetylcholine is hydrolyzed by acetycholinesterase. The mole ratio of acetylcholine to acetic acid is 1:1.
Therefore the moles of acetylcholine = 