A standard drink of beer is 12 ounces
Preparing 15 mg/gl working standard solution from a 20 mg/dl stock solution will require the application of the dilution principle.
Recalling the principle:
initial volume x initial molarity = final volume x final molarity
Since we were not given any volume to work with, we can as well just take an arbitrary volume to be prepared. Let's assume that the stock solution is 10 mL and we want to prepare 15 mg/gl from it:
Applying the dilution principle:
10 x 20 = final volume x 15
final volume = 200/15
= 13.33 mL
This means that in order to prepare 13.33 mL, 15 mg/l working standard solution from 10 ml, 20 mg/dl stock solution, 3.33 mL of the diluent must be added to the stock solution.
More on dilution principle can be found here: brainly.com/question/11493179
Bohr display says obviously the electron spins around the core in orbit. so circle implies a circular locale around core.
Express the oxidation state numerically (e.g., +1).
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Ions
In an ion, the sum of the oxidation states is equal to the overall ionic charge. Note that the sign of the oxidation states and the number of atoms associated with each oxidation state must be considered. In OH−, for example, the oxygen atom has an oxidation state of −2 and the hydrogen atom has an oxidation state of +1, for a total of (−2)+(+1)=−1.
Part C
What is the oxidation state of an individual phosphorus atom in PO33−?
Express the oxidation state numerically (e.g., +1).
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Part D
What is the oxidation state of each individual carbon atom in C2O42−?
Express the oxidation state numerically (e.g., +1).
