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muminat
3 years ago
11

Heat generated by Friction

Chemistry
1 answer:
dimulka [17.4K]3 years ago
4 0

Answer:

The answer is C

Explanation:

because if you pull or push something, friction will always push or pull the opposite way

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Elements in the same period have the same ___________?​
tiny-mole [99]

Answer:

number of energy levels

Explanation:

for example hydrogen and helium are in period 1 and they have 1 energy level

7 0
3 years ago
Boron has two naturally-ocurring isotopes. Boron-10 has an abundance of 19.8% and actual mass of 10.013 amu, and boron-11 has an
aniked [119]

Answer:

Average atomic mass = 10.812 amu

Explanation:

The formula for the calculation of the average atomic mass is:

Average\ atomic\ mass=(\frac {\%\ of\ the\ first\ isotope}{100}\times {Mass\ of\ the\ first\ isotope})+(\frac {\%\ of\ the\ second\ isotope}{100}\times {Mass\ of\ the\ second\ isotope})

Given that:

<u>For first isotope, Boron-10: </u>

% = 19.8 %

Mass = 10.013 amu

<u>For second isotope, Boron-11: </u>

% = 80.2 %

Mass = 11.009 amu

Thus,  

Average\ atomic\ mass=\frac{19.8}{100}\times {10.013}+\frac{80.2}{100}\times {11.009}=1.982574+8.829218=10.811792

<u>Average atomic mass = 10.812 amu</u>

6 0
3 years ago
Read 2 more answers
The letters ROYGBIV represent the colors of visible light. Arrange them in order of:
aleksandrvk [35]
Visible and Ultraviolet Spectroscopy

Violet: 400 - 420 nm.

Indigo: 420 - 440 nm.

Blue: 440 - 490 nm.

Green: 490 - 570 nm.

Yellow: 570 - 585 nm.

Orange: 585 - 620 nm.

Red: 620 - 780 nm.

Hope this helps
4 0
3 years ago
How many grams are in 4.23E44 particles of PbO2
ASHA 777 [7]

1.679 × 10²³ g of PbO₂ is present in 4.23×10⁴⁴ particles of PbO₂.

<u>Explanation:</u>

First the number of particles is converted into moles by dividing it by the Avogadro's number and then moles multiplied by the molar mass, we will get the mass of PbO₂ in grams.

4.23×10⁴⁴/ 6.022×10²³ = 7.02×10²⁰ moles

Now we have to multiply this by the molar mass of PbO₂, that is 239.2 g/mol, we will get the mass in grams.

7.02×10²⁰ moles × 239.2 g/mol = 1.679 × 10²³ g of PbO₂

3 0
3 years ago
How many grams of zinc sulfide are used to produce 1.28 grams of zinc oxide?
Lostsunrise [7]

Answer:

0.012288122055459

Explanation:

i might be wrong

6 0
3 years ago
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