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muminat
3 years ago
11

Heat generated by Friction

Chemistry
1 answer:
dimulka [17.4K]3 years ago
4 0

Answer:

The answer is C

Explanation:

because if you pull or push something, friction will always push or pull the opposite way

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HClO4 acid solution has a concentration of 5 Molarity. Calculate the concentration of this solution in
Nutka1998 [239]

Answer:

1. Percentage by weight = 0.5023 = 50.23 %

2. molar fraction =0.153

Explanation:

We know that

Molar mass of HClO4 = 100.46 g/mol

So the mass of 5 Moles= 5 x 100.46

       Mass (m)= 5 x 100.46 = 502.3 g

Lets assume that aqueous solution of HClO4  and the density of solution is equal to density of water.

Given that concentration HClO4 is 5 M it means that it have 5 moles of HClO4 in 1000 ml.

We know that

Mass = density x volume

Mass of 1000 ml  solution = 1 x 1000 =1000     ( density = 1 gm/ml)

            m'=1000 g

1.

Percentage by weight = 502.3 /1000

Percentage by weight = 0.5023 = 50.23 %

2.

We know that

molar mass of water = 18 g/mol

mass of water in 1000 ml = 1000 - 502.3 g=497.9 g

So moles of water = 497.7 /18 mole

moles of water = 27.65 moles

So molar fraction = 5/(5+27.65)

molar fraction =0.153

6 0
2 years ago
What is meant by atomic number?
SpyIntel [72]
C I hope I help good luck
8 0
2 years ago
When does a change in energy occur?
MrRa [10]
3. in every chemical or physical change
6 0
3 years ago
What is the destiny of an object that has a mass of 20 grams and a volume of 10 millimeters
blondinia [14]

Answer:

2gcm⁻³

Explanation:

Given parameters:

Mass of the object  = 20g

Volume = 10mL

Unknown:

Density of the object  = ?

Solution:

Density of a body is its mass per unit volume;

   Density  = \frac{mass}{volume}  

We need to convert mL to cm³ for the volume

     1mL  = 1cm³;

        10mL is therefore, 10cm³  

So;

       Density  = \frac{20}{10}   = 2gcm⁻³

7 0
2 years ago
mass of 6.584 g. After it is heated, it has a mass of 4.194 g. What is the percentage by mass of water in the hydrate?
Bad White [126]
M₁=6.584 g
m₂=4,194 g

m(H₂O)=m₁-m₂

w(H₂O)=m(H₂O)/m₁

w(H₂O)=(m₁-m₂)/m₁

w(H₂O)=(6.584-4.194)/6.584=0.3630  (36.30%)

the percentage by mass of water in the hydrate 36.30

8 0
3 years ago
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