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Firlakuza [10]
3 years ago
11

The number of lightening bugs active near a pond is given by the function f(x)=4 3x−2 , where x is the number of minutes after d

usk
Is the interval (0, 4) a reasonable solution to describe when there are fewer than 1024 lightening bugs active?
Mathematics
1 answer:
shepuryov [24]3 years ago
4 0

Answer:

No. The interval  (0, 4)  is not a reasonable solution because the left endpoint results in a fraction value for the function and there cannot be a fraction of a lightening bug.

Step-by-step explanation:

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Mary and her family ordered a large pizza for dinner. Half of the pizza is plain and half of the pizza has pepperoni. Mary loves
Julli [10]

Answer:

3/10 of the renaming full pizza has pepperoni

Step-by-step explanation:

Here, we want to calculate how much of the remaining pizza had pepperoni.

From the question, 1/2 has pepperoni and 1/2 is plain without pepperoni

she eats 1/5 of the pizza having pepperoni, this means that she is actually left with some parts is the half having pepperoni

The actual of the half remaining with pepperoni will be 1/2 - 1/5 = 3/10

This means that 3/10 of the remaining full pizza has pepperoni

7 0
3 years ago
Find the area for the following figure
iren2701 [21]

Answer:

The answer I got was 15 3/4 ft 2

4 0
2 years ago
Could a circle be circumscribed around this?​
djyliett [7]

Answer:

no

Step-by-step explanation:

4 0
2 years ago
What is the area of circle C when the radius is 0.4cm
Solnce55 [7]
I think it’s 0.5, sorry if it’s wrong
7 0
2 years ago
Cones A and B both have volume cubic 48 π units, but have different dimensions. Cone A has radius 6 units and height 4 units. Fi
Alex_Xolod [135]

Answer:

A possible solution is that radius of cone B is 2 units and height is 36 units

Step-by-step explanation:

The volume of a cone is given by

V=\frac{1}{3}\pi r^2 h

where

r is the radius

h is the height

Here we are told that both cones A and B have the same volume, which is:

V_A=\frac{1}{3}\pi r_A^2 h_A = 48 \pi

And

V_B=\frac{1}{3}\pi r_B^2 h_B = 48 \pi (2)

We also know that cone A has radius 6 units:

r_A=6

and height 4 units:

h_A=4

For cone B, from eq.(2), we get

\frac{1}{3}r_B^2 h_B = 48\\r_B^2 h_B = 48\cdot 3 =144

One possible solution for this equation is

r_B = 2\\h_B = 36

In fact in this case, we get:

r_B^2 h_B = (2)^2\cdot 36 = 4\cdot 36 = 144

Therefore a possible solution is that radius of cone B is 2 units and height is 36 units, and we know that in this case Cone B has the same volume as cone A because it is told by the problem.

6 0
2 years ago
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