Answer:
k=30
Step-by-step explanation:
The number of mice vary inversely with cats. This is written as:
When there are 3r-19 cats, there are 2r+1 mice
When there are 6r-27 mice, there are r-5 cats.
Taking the values of k above, we have:
Therefore:
What you need to do is find the greatest amount (1) and the lowest amount (1/4) of sap collected and the find how many times the lowest can go into the greatest. (So how many times can 1/4 go into 1). I believe that this is how you would do that.
Answer:
distance = rate x time
3 and 1/5 = 3.2 and 3 and 3/5 = 3.6
distance = 3.2 x 4.5 = 14.4
14.4 = 3.6 x T
T = 14.4 / 3.6 = 4 <--- Pedro's time
Proportion if im not mistaken
is over of percent over 100
14 over 168 and x over 100 . 14 times 100 divided b 168 i believe .
I believe it is GCF because 9v^3 can be factored out of the expression, becoming:
9v^3 (4 - 3v^2)
9v^3 (-3v^2 + 4)
The quadratic in parentheses can be solved, but with the quadratic equation or by graphing.
