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3 years ago

What is the product (3a2b4)(-8ab3)

Mathematics

1 answer:

Alexus [3.1K]3 years ago

7 0

Answer:

-3a²2b²96

Step-by-step explanation:

(3a2b4)(-8ab3)

= (3a×2b×4)(-24×a×b)

multiply together

= (-96)(3a²)(2b²)

= -3a²2b²96

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A line has a y-intercept of 19 and a slope of 9/4. Find the equation of the line.

Taya2010 [7]

Answer:

y=9/4x+19

Step-by-step explanation:

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2 years ago

Helppppppppppppppp pleaseeeeee fasttttt with problem 4

V125BC [204]

Which one is problem number 4?

8 0

2 years ago

Read 2 more answers

Match each function to its corresponding sequence.

givi [52]

The sequence and their functions are:

f(n) = f(n - 1) + 7 ⇒ 3, 10, 17, 24, 31.....
f(n) = f(n - 1) + 4n - 2 ⇒ 3, 9, 19, 33, 51.....
f(n) = 2[f(n - 1)] ⇒ 3, 6, 12, 24, 48.....

<h3>How to match the functions?</h3>

To do this, we simply set values for n and calculate the function values using the current value of n.

So, we have:

Function 1: f(n) = f(n - 1) + 6n - 5 where f(1) = 3

Let n = 2

f(2) = f(1) + 6(2) - 5 = 3 + 12 - 5 = 10

Let n = 3

f(3) = f(2) + 6(3) - 5 = 10 + 18 - 5 = 23

None of the sequence follows the pattern 3, 10, 23....

Function 2: f(n) = f(n - 1) + 2n - 1 where f(1) = 3

Let n = 2

f(2) = f(1) + 2(2) - 1 = 3 + 4 - 1 = 6

Let n = 3

f(3) = f(2) + 2(3) - 1 = 6 + 6 - 1 = 11

None of the sequence follows the pattern 3, 6, 11....

Function 3: f(n) = f(n - 1) + 6 where f(1) = 3

Let n = 2

f(2) = f(1) + 6 = 3 + 6 = 9

Let n = 3

f(3) = f(2) + 6 = 9 + 6 = 15

None of the sequence follows the pattern 3, 9, 15....

Function 4: f(n) = f(n - 1) + 7 where f(1) = 3

Let n = 2

f(2) = f(1) + 7 = 3 + 7 = 10

Let n = 3, 4 and 5

f(3) = f(2) + 7 = 10 + 7 = 17

f(4) = f(3) + 7 = 17 + 7 = 24

f(5) = f(4) + 7 = 24 + 7 = 31

So, we have:

f(n) = f(n - 1) + 7 ⇒ 3, 10, 17, 24, 31.....

Function 5: f(n) = f(n - 1) + 4n - 2 where f(1) = 3

Let n = 2

f(2) = f(1) + 4(2) - 2 = 3 + 8 - 2 = 9

Let n = 3, 4 and 5

f(3) = f(2) + 4(3) - 2 = 9 + 12 - 2 = 19

f(4) = f(3) + 4(4) - 2 = 19 + 16 - 2 = 33

f(5) = f(4) + 4(5) - 2 = 33 + 20 - 2 = 51

So, we have:

f(n) = f(n - 1) + 4n - 2 ⇒ 3, 9, 19, 33, 51.....

Function 6: f(n) = 2[f(n - 1)] where f(1) = 3

Let n = 2

f(2) = 2 * f(1) = 2 * 3 = 6

Let n = 3, 4 and 5

f(3) = 2 * f(2) = 2 * 6 = 12

f(4) = 2 * f(3) = 2 * 12 = 24

f(5) = 2 * f(4) = 2 * 24 = 48

So, we have:

f(n) = 2[f(n - 1)] ⇒ 3, 6, 12, 24, 48.....

Read more about sequence at:

brainly.com/question/6561461

#SPJ1

7 0

1 year ago

Ronisha invests $5000 in an account that earns 2.3% annual simple interest. After 3 years, Ronisha invests the interest earned i

tia_tia [17]

Very complicated problem, but thank goodness I have too much time and am a nerd.

Basically model 1st account as so.
Fv=pv(1+I)^N
Fv future value
Pv present value
I interest
N number years
So first equation is interest earned after 3 years
Y=5000(1+0.023)^3
Y=5353 (rounded up)
So we know that the interest earned is 5353-5000 which is 353.

Now Ronisha (clearly the name of a future investment genius) invests these 353$ in a new account.
Now remember we’re not solving for FV we’re cause we’re given that: 55.2$
However this is the interest earned not the future value. So if interest earned is fv - pv and we know pv
Fv - 353 = 55.2
Fv = 408.2$
So now we reuse the formula
408.2 = 353(1+0.032)^x
Now just solve for x:
First divide both sides by 353
1.156 = 1.032^x
Remember the log rule that states x=b^y is same as y=logb(x)
So using the same logic:
X= log1.032(1.156)
Use some kind of calculator for that where you can adjust log base. But you basically get:
X= 4.602
So Ronisha has to basically invest 5 years or 4.6 years which is 4 years and 7 months.

Omg nevermind, wait it’s simple interest….
Sorry here’s the simple solution. My bad, but I worked so hard on the top part I don’t want to delete it.
I=prt
Interest = principal * rate * time
I= 5000(0.023)(3)=345
Then just do the same but plug 55.2 for I
55.2 = 345(0.032)t
Now solve for t
55.2 = 11.04t
t= 5

As you can see, similar logic where ultimately it takes 5 years. But this “genius” Ronisha should’ve just done compounding interest (my first calculation) and gotten it done in 4.6 years. Almost 5 months faster.

6 0

2 years ago

Jim baked 31 cookies. His family ate m of them. Using m, write an expression for the number of cookies that remained.

Serggg [28]

Answer:

31-m

Step-by-step explanation:

Hope this helps!

4 0

2 years ago

Read 2 more answers