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Answer:
Step-by-step explanation:
Given that Tay-Sachs disease is a genetic disorder that is usually fatal in young children. If both parents are carriers of the disease, the probability that each of their offspring will develop the disease is approximately 0.25.
Let X be the no of children having this disease out of 4 occasions
Then X has two outcomes and each trial is independent of the other trial
Hence X is binomial with n =4, and p = 0.25
a)
b)
c) since independent.