Answer:
1. At the end of S phase- 20 pg DNA
2. At the end of G2 phase- 20 Pg DNA
Explanation:
The cell before undergoing M phase undergoes the steps of interphase that is G₁, S and G₂ phase.
During S phase, the process of cell replication takes place which replicates the DNA as a result of which the amount of DNA doubles. This DNA amount is reduced to half during the anaphase stage of M phase.
In the question since the amount of DNA is 10pg therefore the amount will be double during S phase and becomes 20 pg and will remain 20 pg until the DNA is distributed therefore at the end of G₂ phase Will remain the 20 pg.
I believe lip is -al and nose is palp (not fully sure)
Answer:
20% plus 20% is 40% of adennine and thymine. From 100% DNA bases subtract 40% and you will get 60%. Then divide this by 2 and you will get 30%. 30% of guanine and 30% of cytosine, because their amounts are equal in the DNA stand.
