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2 years ago

2x-y=3 ; 5x+2y=30 solve using elimination

Mathematics

1 answer:

Zigmanuir [339]2 years ago

4 0

Answer:

x = 4, y = 5

Step-by-step explanation:

$2x-y=3\\4x-2y=6$

so:

$4x - 2y = 6\\+ 5x + 2y = 30\\9x= 36\\x=4$

Substitute this into 2x - y = 3:

$8-y=3\\y = 5$

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"A cable TV company wants to estimate the percentage of cable boxes in use during an evening hour. An approximation is 20 percen

Marizza181 [45]

Answer:

The company should take a sample of 148 boxes.

Step-by-step explanation:

Hello!

The cable TV company whats to know what sample size to take to estimate the proportion/percentage of cable boxes in use during an evening hour.

They estimated a "pilot" proportion of p'=0.20

And using a 90% confidence level the CI should have a margin of error of 2% (0.02).

The CI for the population proportion is made using an approximation of the standard normal distribution, and its structure is "point estimation" ± "margin of error"

[p' ± $Z_{1-\alpha /2} * \sqrt{\frac{p'(1-p')}{n} }$ ]

Where

p' is the sample proportion/point estimator of the population proportion

$Z_{1-\alpha /2} * \sqrt{\frac{p'(1-p')}{n} }$ is the margin of error (d) of the confidence interval.

$Z_{1-\alpha /2} = Z_{1-0.05} = Z_{0.95}= 1.648$

$d= Z_{1-\alpha /2} * \sqrt{\frac{p'(1-p')}{n} }$

$d *Z_{1-\alpha /2}= \sqrt{\frac{p'(1-p')}{n} }$

$(d*Z_{1-\alpha /2})^2= \frac{p'(1-p')}{n}$

$n*(d*Z_{1-\alpha /2})^2= p'(1-p')$

$n= \frac{p'(1-p')}{(d*Z_{1-\alpha /2})^2}$

$n= \frac{0.2(1-0.2)}{(0.02*1.648)^2}$

n= 147.28 ≅ 148 boxes.

I hope it helps!

3 0

3 years ago

In the following, after distributing and solving, find the error.

larisa86 [58]

After 6x+48=72, you have to subtract 48 on both sides not add. Your final answer will be x=4. 72-48=24.. 24/6= 4.

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3 years ago

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2 years ago

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Triss [41]

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3 years ago

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Ezekiel bought a 18 ounce box of chocolate for $6.50. What was the cost per ounce? in a explanation order

vivado [14]

Answer:0.36

Step-by-step explanation:

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3 years ago