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Nadusha1986 [10]
3 years ago
8

F function g has the factors (x − 7) and (x + 6), what are the zeros of function g?

Mathematics
1 answer:
Allisa [31]3 years ago
4 0

Answer:

Zeros are 7 and -6

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In a hostel, 120 students had provisions of food for 60 days. After 20 days, some students were added to the hostel, the provisi
DochEvi [55]

Answer:

If I'm right, the answers should be 40.

8 0
3 years ago
Write the slope intercept form of the equation of the line through the given point
ozzi

Answer:

y =  -\frac{3}{4}x

Step-by-step explanation:

slope-intercept form: y = mx + b

Given: slope(m) = -\frac{3}{4}, point (4, -3)

We already have the value of m, but we need to find the value of b. To do this, input the given values of the slope and the point into the equation:

-3 =  -\frac{3}{4}(4) + b

Solve for b:

-3 =  -\frac{3}{4}(4) + b

-3 = -3 + b

0 = b

The value of b is zero. We can now write the equation:

y =  -\frac{3}{4}x + 0

y =  -\frac{3}{4}x

The equation written in slope-intercept form is: y =  -\frac{3}{4}x

8 0
3 years ago
Lutfen soruyu cevaplayın ​
elena-s [515]

Answer:

huh????

Step-by-step explanation:

what did you try to say

8 0
3 years ago
In the figure, AB║CD and ∠EIA is congruent to ∠GJB Complete the following statements to prove that ∠IKL is congruent to ∠DLH.
Finger [1]

Here it is given that AB || CD

< EIA = <GJB

Now

∠EIA ≅ ∠IKC and ∠GJB is ≅ ∠ JLD (Corresponding angles)

∠EIA  ≅ ∠GJB then ∠IKC ≅ ∠ JLD (Substitution Property of Congruency)

∠IKL + ∠IKC 180° and ∠DLH +  ∠JLD =180° (Linear Pair Theorem)

So

m∠IKL + m∠IKC = 180°       ....(1)

But ∠IKC  ≅ ∠JLD

m∠IKC = m∠JLD (SUBTRACTION PROPERTY OF CONGRUENCY)

So we have

m∠IKL + m∠JLD = 180°

∠IKL and ∠JLD are supplementary angles.

But ∠DLH and ∠JLD are supplementary angles.

∠IKL ≅ ∠DLH (CONGRUENT SUPPLEMENTS THEOREM)

7 0
3 years ago
Read 2 more answers
If (x^2−1)/(x+1) = 3x + 5, then x + 3 =<br> (A) -3<br> (B) -2<br> (C) 0<br> (D) 2<br> (E) 4
sineoko [7]
The answer is C) 0
Because math
4 0
3 years ago
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