A rocket is launched from a tower. The height of the rocket, y in feet, is related to the time after launch, x in seconds, by th
e given equation. Using this equation, find the time that the rocket will hit the ground, to the nearest 100th of second.
y=-16x^2+116x+75
2 answers:
Answer:
7.85
Step-by-step explanation:
the other guy is incorrect,
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Integers involve with negative, so D isn't the correct answer the correct answer will be A.
Answer:
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Step-by-step explanation: They only cross once
You can use either of these, depending on your teacher.
2.e+14
2.0*10^14
Answer:
I'm guessing 12 not sure why just guessing
Answer: -2,3,&4
Step-by-step explanation:
Correct on edgenuity
