The answer:
The width is 7cm
Answer:
Step-by-step explanation:
We know that the length is four times the width, so:
We also know the area, which is 324 m². The formula for area:
Insert the known values:
Solve for w. Simplify by removing parentheses:
Divide 4 from both sides to isolate the variable:
Find the square root of both sides:
The width is 9 m.
We know the width. Now find the length by using the area formula and inserting known values:
Solve for l. Divide both sides by 9:
The length of the rectangle is 36. (You can check: 4 times 9 is 36)
Now find the perimeter:
Insert values:
The perimeter is 90 m.
C(a,b), because the x-coordinate( first coordinate) is a (seeing as it is situated directly above point B, which also has an x-coordinate of a) and the y-coordinate ( second coordinate) is b (seeing as it is situated on the same horizontal level as point D, which also has a y-coordinate of b)
the length of AC can be calculated with the theorem of Pythagoras:
length AB = a - 0 = a
length BC = b - 0 = b
seeing as the length of AC is the longest, it can be calculated by the following formula:
It is called "Pythagoras' Theorem" and can be written in one short equation:
a^2 + b^2 = c^2 (^ means to the power of by the way)
in this case, A and B are lengths AB and BC, so lenght AC can be calculated as the following:
a^2 + b^2 = (length AC)^2
length AC = √(a^2 + b^2)
Extra information: Seeing as the shape of the drawn lines is a rectangle, lines AC and BD have to be the same length, so BD is also √(a^2 + b^2). But that is also stated in the assignment!
(i) The percentage of students who got high scores in both the subjects English and Mathematics is 46%.
(ii) The total number of students who got high scores either in Mathematics or in English if 300 students had attended the exam exists 138.
<h3>What is probability?</h3>
The probability exists in the analysis of the possibilities of happening of an outcome, which exists acquired by the ratio between favorable cases and possible cases.
The number of students who got high scores in Mathematics was 75%.
The number of students who got high scores in English was 65%.
(i) The percentage of students who got high scores in both the subjects
100% - 6% = 94%
(75% + 65%) - 94%
= 140% - 94%
= 46%
Therefore, the percentage of students who got high scores in both the subjects English and Mathematics is 46%.
(ii) The total number of students who got high scores either in Mathematics or in English if 300 students had attended the exam
= 300 46%
= 300 (46 / 100)
= 300 0.46
= 138.
Therefore, the total number of students who got high scores either in Mathematics or in English if 300 students had attended the exam exists 138.
To learn more about probability refer to:
brainly.com/question/13604758
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