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saw5 [17]
3 years ago
8

I ready true or false question.

Mathematics
2 answers:
STALIN [3.7K]3 years ago
4 0

Answer:

true

Step-by-step explanation:

Nadya [2.5K]3 years ago
3 0
True because the tenth might go up, but the 8 will not go up to a nine because 3 is still less than 5
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Charles has 24 marbles. He has 6 more marbles than blue marbles. Which equation represents this situation.
statuscvo [17]

Answer:

n + (n + 6) = 24.

Step-by-step explanation:

Let him have n  blue marbles, then he has n + 6 other narbles.

He has a total of 24 marbles, so:

n + (n + 6) = 24.

8 0
2 years ago
Read 2 more answers
The highest point in the United states is mount McKinley also called denali
pogonyaev

Yes, it this somehow related to mathematics? Was this a question?

3 0
2 years ago
How many solutions can be found for the system of linear equations represented on the graph?
Alexxandr [17]
Answer: D) infinitely many solutions

Explanation: because the lines overlap each other every single point is a solution, therefore infinitely many solutions
3 0
3 years ago
Sketch a graph of f(x)
just olya [345]

Answer:

The graph in the attached figure  

Step-by-step explanation:

we know that

For x\leq -2 -----> the interval is (-∞,-2]

f(x)=-3

For -2 < x \leq 1 -----> the interval is (-2,1]

f(x)=x

For x > 1 -----> the interval is (1,∞)

f(x)=2

The graph in the attached figure

3 0
3 years ago
Plz help me!!!
Nadya [2.5K]
To solve this we are going to use the exponential function: f(t)=a(1(+/-)b)^t
where
f(t) is the final amount after t years
a is the initial amount
b is the decay  or grow rate rate in decimal form
t is the time in years

Expression A 
f(t)=624(0.95)^{4t}
Since the base (0.95) is less than one, we have a decay rate here.
Now to find the rate b, we are going to use the formula: b=|1-base|*100%
b=|1-0.95|*100%
b=0.05*100%
b=5%
We can conclude that expression A decays at a rate of 5% every three months.

Now, to find the initial value of the function, we are going to evaluate the function at t=0
f(t)=624(0.95)^{4t}
f(0)=624(0.95)^{0t}
f(0)=624(0.95)^{0}
f(0)=624(1)
f(0)=624
We can conclude that the initial value of expression A is 624.

Expression B
f(t)=725(1.12)^{3t}
Since the base (1.12) is greater than 1, we have a growth rate here.
To find the rate, we are going to use the same equation as before:
b=|1-base|*100%
b=|1-1.12|*100
b=|-0.12|*100%
b=0.12*100%
b=12%
We can conclude that expression B grows at a rate of 12% every 4 months.

Just like before, to find the initial value of the expression, we are going to evaluate it at t=0
f(t)=725(1.12)^{3t}
f(0)=725(1.12)^{0t}
f(0)=725(1.12)^{0}
f(0)=725(1)
f(0)=725
The initial value of expression B is 725.

We can conclude that you should select the statements:
- Expression A decays at a rate of 5% every three months, while expression B grows at a rate of 12% every fourth months. 

- Expression A has an initial value of 624, while expression B has an initial value of 725.

8 0
3 years ago
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