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saw5 [17]
4 years ago
8

I ready true or false question.

Mathematics
2 answers:
STALIN [3.7K]4 years ago
4 0

Answer:

true

Step-by-step explanation:

Nadya [2.5K]4 years ago
3 0
True because the tenth might go up, but the 8 will not go up to a nine because 3 is still less than 5
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Suppose you buy a new car whose advertised mileage is 23 miles per gallon​ (mpg). After driving your car for several​ months, yo
Sedbober [7]

Answer:

B.

Step-by-step explanation:

7 0
3 years ago
Read 2 more answers
S=a1/1-r
valentinak56 [21]

Answer:

4

Step-by-step explanation:

This is an <em>infinite geometric series</em>. This has a sum of  \frac{a}{1-r}

Where

a is the first term, and

r is the common ratio (one term divided by the previous term)

Let's figure out the first 2 terms by plugging in n = 1 first and then n = 2 for the series.

<u />

<u>First term:</u>

3(\frac{1}{4})^{n-1}\\=3(\frac{1}{4})^{1-1}\\=3(\frac{1}{4})^0\\=3(1)\\=3

<u>Second term:</u>

3(\frac{1}{4})^{n-1}\\=3(\frac{1}{4})^{2-1}\\=3(\frac{1}{4})^1\\=3(\frac{1}{4})\\=\frac{3}{4}

<em>Let's see the common ratio:  \frac{\frac{3}{4}}{3}\\=\frac{3}{4}*\frac{1}{3}\\=\frac{1}{4}</em>

<em />

<em>Thus we have a = 3 and r = 1/4</em><em>. Plugging into the formula of the infinite sum, we get:</em>

<em>s=\frac{a}{1-4}=\frac{3}{1-\frac{1}{4}}=\frac{3}{\frac{3}{4}}=3*\frac{4}{3}=4</em>

<em />

<em>So, </em><em>the answer is 4</em>

4 0
3 years ago
Is the ratios : equivalent to : ? *
cluponka [151]

Answer:

What is the question?

Step-by-step explanation:

7 0
3 years ago
Which formula can be used to find the nth term of the geometric sequence below?
diamong [38]

Answer:

nth term =  (1/6)(6)^(n-1).

Step-by-step explanation:

The first term a1 = 1/6 and the common  ratio r =  1 / 1/6 = 6, also 36/6 = 6 which confirms this.

So the nth term = a1 r^(n - 1)

= (1/6) 6^(n-1).

8 0
4 years ago
Help please! :) 20 points!!
Lelechka [254]
Hi,

Answer: D

\sqrt{160}  = 40

Hope this helps.
r3t40
3 0
3 years ago
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