Answer:
4
Step-by-step explanation:
This is an <em>infinite geometric series</em>. This has a sum of 
Where
a is the first term, and
r is the common ratio (one term divided by the previous term)
Let's figure out the first 2 terms by plugging in n = 1 first and then n = 2 for the series.
<u />
<u>First term:</u>

<u>Second term:</u>

<em>Let's see the common ratio:
</em>
<em />
<em>Thus we have a = 3 and r = 1/4</em><em>. Plugging into the formula of the infinite sum, we get:</em>
<em>
</em>
<em />
<em>So, </em><em>the answer is 4</em>
Answer:
What is the question?
Step-by-step explanation:
Answer:
nth term = (1/6)(6)^(n-1).
Step-by-step explanation:
The first term a1 = 1/6 and the common ratio r = 1 / 1/6 = 6, also 36/6 = 6 which confirms this.
So the nth term = a1 r^(n - 1)
= (1/6) 6^(n-1).