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3 years ago

PLEASEEE HELP!!!!........................

Mathematics

1 answer:

Snowcat [4.5K]3 years ago

5 0

In this question you have to multiply and simplify to get answer

$(5-\sqrt{2} )(-3+\sqrt{5})$

Using identity (a + b)(c + d) = ac + ad + bc + bd we can multiply both polynomials

$= (5)(-3) + (5)(\sqrt{5}) + (-\sqrt{2})(-3) + (-\sqrt{2})(\sqrt{5})$

$= -15 + 5\sqrt{5}+ 3\sqrt{2}-\sqrt{2*5}$

$= -15 + 5\sqrt{5}+ 3\sqrt{2}-\sqrt{10}$

Therefore the answer $= -15 + 5\sqrt{5}+ 3\sqrt{2}-\sqrt{10}$

Happy to help :)

If you need anymore help, pls ask

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What is the maximum volume in cubic inches of an open box to be made from a 12-inch by 16-inch piece of cardboard by cutting out

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I need the answers for these pls help

DanielleElmas [232]

Answer:

A. m arc QRS = 100°

B. m arc QRT = 255°

C. m arc UTS = 180°

D. m arc UTR = 205°

1] The major arc CA = 255°

2] The minor arc AB = 90°

Step-by-step explanation:

In a circle:

The measure of an central angle is equal to the measure of its subtended arc
The measure of a circle is 360°
Any chord divides a circle into two arcs, a minor arc its measure is < 180° and a major arc its measure is > 180°, the sum of the measures of the minor and major arcs is 360°
If the measures of the minor and major arcs are equal, then each arc represents a semi-circle

In circle O

∵ m∠QOR = 75°

∵ ∠QOR subtended by arc QR

- By using the 1st note above

∴ m of arc QR = m∠QOR

∴ m of arc QR = 75°

∵ m∠ROS = 25°

∵ ∠ROS subtended by arc RS

∴ m of arc RS = m∠ROS

∴ m of arc RS = 25°

The measure of arc QRS is the sum of the measures of arcs QR and RS

∴ m arc QRS = 75° + 25° = 100°

∵ m∠SOT = 155°

∵ ∠SOT subtended by arc ST

∴ m of arc ST = m∠SOT

∴ m of arc ST = 155°

The measure of arc QRT is the sum of the measures of arcs QR, RS and ST

∴ m arc QRT = 75° + 25° + 155 °= 255°

∵ m∠UOT = 25°

∵ ∠UOT subtended by arc UT

∴ m of arc UT = m∠UOT

∴ m of arc RUT = 25°

The measure of arc UTS is the sum of the measures of arcs UT and TS

∴ m arc UTS = 25° + 155° = 180°

The measure of arc UTR is the sum of the measures of arcs UT, TS and SR

∴ m arc UTR = 25° + 155° + 25 = 205°

∵ The sum of the measures of the minor and major arcs is 360°

∵ m of minor arc AC = 105°

- Subtract 105 from 360° to find the measure of the major arc CA

∴ m of major arc CA = 360° - 105°

∴ m of major arc CA = 255°

∵ m of major arc AB = 270°

- Subtract 270° from 360° to find the measure of the minor arc AB

∴ m of minor arc AB = 360° - 270°

∴ m of minor arc AB = 90°

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