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2 years ago

8

$12,500 is invested, part at 9% and the rest at 5%. If the interest earned from the amount invested at 9% exceeds the interest e

arned from the amount invested at 5% by $486.00, how much is invested at each rate?

1 answer:

marysya [2.9K]2 years ago

4 0

Answer:

$1,538.00

Step-by-step explanation:

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Please help with this i’ll give brainliest

cricket20 [7]

Answer:

<em>Answer to part A:</em>

1 notebook = $2.5

1 pen = $1.5

<em>Answer to part B:</em>

= 3 pens.

Step-by-step explanation:

<em>Here's the simultaneous equation.</em>

4n + 3p = $14.50

5n + 6p = $21.50

<em>Multiply the numerator by the denominators first number and vice-versa.</em>

5(4n + 3p) = $14.50

4(5n + 6p) =$ 21.50

<em>Here's what you should get.</em>

20n + 15p = $72.50

20n + 24p = $86

<em>Eliminate the like numbers by subtracting the denominator from the numerator.</em>

20n - 20n = 0

15p - 24p = -9p

$72.50 - $86 = -$13.5

<em>Divide the result after the equal sign by the result before the equal sign.</em>

-$13.5 ÷ -9 = $1.5p

<em>Since we've found the cost of one pen as $1.5, lets substitute any of the first equations to get the cost of one notebook.</em>

4n + 3p = $14.50

4n + 3($1.5) = $14.50

4n + $4.5 = $14.50

4n = $14.50 - $4.5

4n = $10.00

n = $2.5

<em>Here's the answer to part A:</em>

1 notebook = $2.5

1 pen = $1.5

<em>Part B::::::::::::::::::</em>

1 ($1.5) = 3($2.5)

$1.5 + $7.5 = $9.0

$27 ÷ 9 = $3

<em>Therefore, she'll buy each supply thrice:</em>

3 ( $1.5 + $7.5 ) = 3 ( $9.0 )

( $4.5 + $22.5 ) = ( $27 )

$4.5 + $22.5 = $27

<em>Answer to part B:</em>

= 3 pens.

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3 0

2 years ago

We have 9 pens, of which 5 are green ink, 3 are red ink, and 1 is black. If we put the pens in a line, how many arrangements are

Pavel [41]

Answer:

504 arrangements are possible

Step-by-step explanation:

Arrangements of n elements:

The number of arrangements of n elements is given by:

$A_{n} = n!$

Arrangements of n elements, divided into groups:

The number of arrangements of n elements, divided into groups of $n_1, n_2,...,n_n$ elements is given by:

$A_{n}^{n_1,n_2,...,n_n} = \frac{n!}{n_1!n_2!...n_n!}$

In this case:

9 pens, into groups of 5, 3 and 1. So

$A_{9}^{5,3,1} = \frac{9!}{5!3!1!} = 504$

504 arrangements are possible

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3 years ago

A pet store has 10 puppies, including 4 poodles, 3 terriers and 3 retrievers. If Rebecca and Aaron in that order each select one

VikaD [51]

4/20, 20% chance. The store has 20 puppies. Out of them is 4 poodles. Divide 4 by the total(20). And you get 0.2, remove the decimal place and add it in front of the 0 .02 reverse the numbers 20. Replace the period with a %.

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2 years ago

How to decompose 9/10 in 3 ways

egoroff_w [7]

Is this what you needed?

8 0

3 years ago

There are 52 cards in a standard deck: 13 hearts, 13 clubs, 13 diamonds , and 13 spades. Timothy draws four cards at random from

siniylev [52]

Answer:

$\dfrac{1}{4}$

Step-by-step explanation:

Total number of cards in a standard deck = 52

Number of hearts in the deck = 13

Number of clubs in the deck = 13

Number of diamonds in the deck = 13

Number of spades in the deck = 13

Four cards are drawn at random by Timothy.

These four cards are drawn from each one of the suits.

And the cards are not replaced.

Therefore, now cards remaining in each suit:

Remaining number of hearts in the deck = 12

Remaining number of clubs in the deck = 12

Remaining number of diamonds in the deck = 12

Remaining number of spades in the deck = 12

Formula for probability of an event E can be observed as:

$P(E) = \dfrac{\text{Number of favorable cases}}{\text {Total number of cases}}$

Here, number of favorable cases are 12 (i.e. number of hearts)

Total number of cases = 12 $\times$ 4 = 48

Therefore, the required probability is:

$\dfrac{12}{48} = \bold{\dfrac{1}4}$

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2 years ago