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Ahat [919]
3 years ago
10

an ice cream company did a survey among high school students. it was found that 86 students liked vanilla ice cream and 48 of th

ose students liked chocolate ice cream also. there were 12 students who did not like vanilla ice cream but liked chocolate ice cream. there were 2 students who did not like either vanilla ice cream or chocolate ice cream. using a two-way table, predict the number of students who would like chocolate ice cream when 500 high school students participate in the survey. 250 300 350 400
Mathematics
1 answer:
Kitty [74]3 years ago
4 0

Answer:

300

Step-by-step explanation:

Students like Vanilla ice cream = 86

Out of 86 Students like chocolate ice cream too = 48

So, No. of students who like only vanilla=86-48 = 38

There were 12 students who did not like vanilla ice cream but liked chocolate ice cream.

There were 2 students who did not like either vanilla ice cream or chocolate ice

                                   Like Vanilla      Did not like vanilla     Total

Like Chocolate             48                           12                           60

Did not like chocolate  38                           2                             40      

Total                               86                          14                            100

No. of students who like chocolate out of 100 = 60

Now we are supposed to find the number of students who would like chocolate ice cream when 500 high school students participate in the survey.

Let x be the number of students out of 500 who like chocolate

So, A.T.Q

\frac{60}{100}=\frac{x}{500}

\frac{60}{100} \times 500=x

300=x

Hence the number of students who would like chocolate ice cream when 500 high school students participate in the survey is 300.

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2 years ago
given the line AB with A(1,4) and B(-3,-1) is parallel to line CD with C(8,3) and D(x,-7), solve for the missing value of x.​
umka2103 [35]

Answer:

x = 0

Step-by-step explanation:

We can find the missing value by solving for the other points (graphically or algebraically). We would first find the line of Points A and B in order to find the parallel line that would help us find the coordinate point with the x-value.

1) Graph points A, B, and C.

2) Calculate the slope of points A and B by using the slope formula:

y2 - y1/x2 - x1.  

-1 - 4/-3 - 1....The slope is 5/4.

3) Write 4 = 5/4(x) + b

**We get 4 from the point A (1, 4)

Plug 1 into x and solve for 4 in order to get your y-intercept.

4 = 5/4(1) + b

4 = 5/4 +b

**If 1 = 4/4, then 4 = 16/4.

16/4 = 5/4 + b

11/4 = b

2.75 = b

4) So our y-intercept is 2.75. We now have an equation of  y = 5/4x + 2.75 (graph it along with points A and B to see that it intersect both points.

5) Now we will use that line to find a line parallel to it. We know that if two lines have the same slope then they are parallel, so for the equation of the parallel line, we write: y = 5/4x + b so far.

6) We will find the y-intercept and use that to find the x-value of point D.

First we plug in the x and y values of point C to find the y-intercept

y = 5/4x + b --> 3 = 5/4(8) + b --> 3 = 40/4 + b --> 3 = 10 + b --> -7 = b

7) Now we have the equation of the line that is parallel to line AB: y = 5/4x -7

To find the missing value of x, plug the y-value of point D into the equation and solve for x.

--> -7 = 5/4x -7

--> x = 0

**You can double check this by graphing each point and both equations for the lines.

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