M = mass of aluminium = 1.11 kg
= specific heat of aluminium = 900
= initial temperature of aluminium = 78.3 c
m = mass of water = 0.210 kg
= specific heat of water = 4186
= initial temperature of water = 15 c
T = final equilibrium temperature = ?
using conservation of heat
Heat lost by aluminium = heat gained by water
M ( - T) = m (T - )
(1.11) (900) (78.3 - T) = (0.210) (4186) (T - 15)
T = 48.7 c
The resulting change in the magnetic flux is =0.013Wb
what is magnetic flux?
Magnetic flux is defined as the number of magnetic field lines passing through a given closed surface. It provides the measurement of the total magnetic field that passes through a given surface area
Given:
At degree =15.5°,magnetic flux=magnetic field=0.500T
At degree=45.0°, magnetic field=0.500T
Magnetic flux=magnetic field ×Area×cos(angle)
magnetic flux (1) = 0.500×0.1×cos(15.5)
= 0.048
magnetic flux (2) = 0.500×0.1×cos(45)
=0.035
Resulting change in flux = 0.048-0.035
= 0.013Wb
learn more about magnetic flux from here: brainly.com/question/28179515
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Yes u can help I need to see th worksheet to help tho
Wouldn't everything fall?
Yes that is correct. We know this because 4.00 x 10 4 Pa is constant. If you have 2.00×10−3m3 then you do the following: (2.00×10^−3)(4.00×10^<span> 4) = </span>8.00×10^−3. That is how you get your answer
