Higher frequency sound waves are perceived as having higher pitch
W= F x dPower (formula)P= W/tForce (formula)F= m x anewton (N)the SI unit for force , equal to 1 kg*m/s2joule (J)<span>the SI unit of work, equal to 1 newton-meter</span>
Terminal velocity is the maximum velocity attainable by an object as it falls through a fluid and is given by,
Where,
m = mass of the falling object.
g = the acceleration due to gravity.
\rho = the density of the fluid the object is falling through.
A = the projected area of the object.
C = the drag coefficient.
A) Because a drop is difficult to approximate to a certain form, it usually tends to be considered a spectrum, the terminal velocity for a sphere is given by
Whatever our appreciations, all the variables are constant, except for the Diameter, we can realize that the terminal velocity is proportional to the radius of the object, the greater the radius - the larger the drop - the greater the terminal velocity.
B) Since there is a "constant" terminal velocity at the end of the path, at which point the forces are balanced, the acceleration will be 0. For both objects.
Answer:
The smallest microwave frequency is 1.5 GHz.
Explanation:
Given that,
Distance d= 20 cm
We need to calculate the wavelength
Using formula for maximum diffraction
For maximum,
We need to calculate the frequency
Hence, The smallest microwave frequency is 1.5 GHz.
Answer: V = 15 m/s
Explanation:
As stationary speed gun emits a microwave beam at 2.10*10^10Hz. It reflects off a car and returns 1030 Hz higher. The observed frequency the car will be experiencing will be addition of the two frequency. That is,
F = 2.1 × 10^10 + 1030 = 2.100000103×10^10Hz
Using doppler effect formula
F = C/ ( C - V) × f
Where
F = observed frequency
f = source frequency
C = speed of light = 3×10^8
V = speed of the car
Substitute all the parameters into the formula
2.100000103×10^10 = 3×10^8/(3×10^8 -V) × 2.1×10^10
2.100000103×10^10/2.1×10^10 = 3×108/(3×10^8 - V)
1.000000049 = 3×10^8/(3×10^8 - V)
Cross multiply
300000014.7 - 1.000000049V = 3×10^8
Collect the like terms
1.000000049V = 14.71429
Make V the subject of formula
V = 14.71429/1.000000049
V = 14.7 m/s
The speed of the car is 15 m/s approximately