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olga55 [171]
3 years ago
13

A particle on a spring moves in simple harmonic motion along the x axis between turning points at x1 = 95 cm and x2 = 135 cm. (i

) At which of the following positions does the particle have maximum speed? 95 cm 105 cm 115 cm at none of those positions (ii) At which position does it have maximum acceleration? 95 cm 105 cm 115 cm at none of those positions (iii) At which position is the greatest net force exerted on the particle? 95 cm 105 cm 115 cm at none of those positions
Physics
1 answer:
uranmaximum [27]3 years ago
8 0

Answer:

(i) x = 115\,cm, (ii) x = 95\,cm, (iii) x = 95\,cm

Explanation:

(i) x_{1} and x_{2} represent the points where particle has a velocity of zero and spring reach maximum deformation, Given the absence of non-conservative force and by the Principle of Energy Conservation, the position where particle is at maximum speed is average of both extreme positions:

x = 115\,cm

(ii) Maximum accelerations is reached at x_{1} and x_{2}.

x = 95\,cm

(iii) Greatest net forces exerted on the particle are reached at  x_{1} and x_{2}.

x = 95\,cm

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a) The magnitude of the force is 968 N

b) For a constant speed of 30 m/s, the magnitude of the force is 1,037 N

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<em>NOTE: The question b) will be changed in other to give a meaningful answer, because it is the same speed as the original (the gallons would be 1.9, as in the original).</em>

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d = 106 km = 106,000 m

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b) We will calculate the force for a speed of 30 m/s.

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6 0
3 years ago
While playing a scavenger hunt game, Anthony walks 48.0 m to the south and then walks 12.0 m to the west. What single straight-l
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To obtain the angle at which Anthony walks 49.48, we obtain the arc tangent of (12/48). This is shown below:

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Therefore, Anthony could have walked 49.48 m towards the S 14.04 W direction.
4 0
3 years ago
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