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11111nata11111 [884]
3 years ago
15

Which kind of pressure prevents stars of extremely large mass from forming?

Physics
2 answers:
wariber [46]3 years ago
7 0

Answer:

radiation pressure

Explanation:

This is the type of pressure that can be applied on any surface as a result of the exchange of momentum that exists between the object and the electromagnetic field. Radiation pressure generates small amount of forces and cannot be easily noticed although such forces are essential in certain physical processes.

Example is momentum of light or electromagnetic radiation which as any wavelength, in which this wavelength can be absorbed, reflected by matter on any scale.

elena-14-01-66 [18.8K]3 years ago
3 0

Answer:

Radiation pressure

Explanation:

Radiation pressure is gotten from the light source. The radiation pressure has a set mass limit of 150 solar masses. Any mass from 150 solar masses or below supports the formation of the stars.

However when the mass exceeds 150 solar masses the force of gravity is unable to hold the masses together and the excess mass

Is usually blown away after which the required mass is then used in the formation.

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Which part of an object's rate of change best defines acceleration?
grandymaker [24]
I believe it is speed.

Hope this helps!
5 0
3 years ago
Read 2 more answers
Como un astronauta utiliza la fuerza de hallar y empujar?
PilotLPTM [1.2K]

Answer:

La única manera en que nuestro astronauta sería capaz de empujar la nave espacial en el espacio sin alejarse sería usar algo llamado "unidad de propulsión de astronauta". Supongamos que el astronauta está usando un SPK soviético, el sistema de cohetes mochila más poderoso jamás utilizado en el espacio.

Explanation:

3 0
3 years ago
NASA communicates with the Space Shuttle and International Space Station using Ku-band microwave radio. Suppose NASA transmits a
jeyben [28]

Answer:

λ₁ = 2.50 10⁻² m,   λ₂ = 1.66 10⁻² m  

Explanation:

Microwave communication is very efficient because it does not have atmospheric interference, for which it is widely used and has been regulated to avoid interference, the ku band is in the range between 12 and 18 GHz.

Let's calculate the wavelength for the two extreme frequencies of this band

wavelength and frequency are related

         c = λ f

          λ = c / f

f₁ = 12 GHz = 12 10⁹ Hz

          λ₁ = 3 10⁸ /12 10⁹

           λ₁ = 2.50 10⁻² m

f₂ = 18 GHz = 18 10⁹ Hz

          λ₂ = 3 10⁸ /18 10⁹

          λ₂ = 1.66 10⁻² m

Unfortunately in your exercise the specific frequency is not fired, for significant figures they must be the same number as the figures of the frequency, in general the frequency has 3 or 4 significant figures

8 0
3 years ago
A truck travels up a hill with a 5.4° incline. The truck has a constant speed of 25 m/s. What is the horizontal component of the
goldenfox [79]

Answer:

v_{x}=24.88m/s

v_{y}=2.35m/s

Explanation:

Knowing that the truck travels up a hill with a 5.4º incline

The horizontal component of the truck's velocity is:

v_{x}=vcos\beta=(25m/s)cos(5.4)=24.88m/s

The vertical component of the truck's velocity is:

v_{y}=vsin\beta=(25m/s)sin(5.4)=2.35m/s

8 0
3 years ago
Answer this plssss<br>12th question<br><br>This is a question which they asked in board
Kisachek [45]

I don't know I'm just a troll.

8 0
3 years ago
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