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11111nata11111 [884]
4 years ago
15

Which kind of pressure prevents stars of extremely large mass from forming?

Physics
2 answers:
wariber [46]4 years ago
7 0

Answer:

radiation pressure

Explanation:

This is the type of pressure that can be applied on any surface as a result of the exchange of momentum that exists between the object and the electromagnetic field. Radiation pressure generates small amount of forces and cannot be easily noticed although such forces are essential in certain physical processes.

Example is momentum of light or electromagnetic radiation which as any wavelength, in which this wavelength can be absorbed, reflected by matter on any scale.

elena-14-01-66 [18.8K]4 years ago
3 0

Answer:

Radiation pressure

Explanation:

Radiation pressure is gotten from the light source. The radiation pressure has a set mass limit of 150 solar masses. Any mass from 150 solar masses or below supports the formation of the stars.

However when the mass exceeds 150 solar masses the force of gravity is unable to hold the masses together and the excess mass

Is usually blown away after which the required mass is then used in the formation.

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Answer by mimiwhatsup: B) Velocity is a vector and requires a direction to completely describe it.

Velocity is the speed and direction of an object in motion.



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4 years ago
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John recently suffered a blow to his head. Since then, he finds it difficult to comprehend what others say to him. He also finds
katovenus [111]

Answer: ​Wernicke's aphasia

Explanation:

John recently suffered a blow to his head. Since then, he finds it difficult to comprehend what others say to him. He also finds it difficult to express his thoughts and cannot seem to find the right words to say while speaking. However, he can speak freely with proper syntax. In this scenario, John is most likely suffering from Wernicke's aphasia.

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6 0
3 years ago
a flag of mass 2.5 kg is supported by a single rope. A strong horizontal wind exerts a force of 12 N on the flag. Calculate the
tatuchka [14]
The free-body diagram of the forces acting on the flag is in the picture in attachment.

We have: the weight, downward, with magnitude
W=mg = (2.5 kg)(9.81 m/s^2)=24.5 N
the force of the wind F, acting horizontally, with intensity
F=12 N
and the tension T of the rope. To write the conditions of equilibrium, we must decompose T on both x- and y-axis (x-axis is taken horizontally whil y-axis is taken vertically):
T \cos \alpha -F=0
T \sin \alpha -W=
By dividing the second equation by the first one, we get
\tan \alpha =  \frac{W}{F}= \frac{24.5 N}{12 N}=2.04
From which we find
\alpha = 63.8 ^{\circ}
which is the angle of the rope with respect to the horizontal.

By replacing this value into the first equation, we can also find the tension of the rope:
T= \frac{F}{\cos \alpha}= \frac{12 N}{\cos 63.8^{\circ}}=27.2 N




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4 years ago
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The surrounding environment cool off is the answer
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