I believe it is speed.
Hope this helps!
Answer:
La única manera en que nuestro astronauta sería capaz de empujar la nave espacial en el espacio sin alejarse sería usar algo llamado "unidad de propulsión de astronauta". Supongamos que el astronauta está usando un SPK soviético, el sistema de cohetes mochila más poderoso jamás utilizado en el espacio.
Explanation:
Answer:
λ₁ = 2.50 10⁻² m, λ₂ = 1.66 10⁻² m
Explanation:
Microwave communication is very efficient because it does not have atmospheric interference, for which it is widely used and has been regulated to avoid interference, the ku band is in the range between 12 and 18 GHz.
Let's calculate the wavelength for the two extreme frequencies of this band
wavelength and frequency are related
c = λ f
λ = c / f
f₁ = 12 GHz = 12 10⁹ Hz
λ₁ = 3 10⁸ /12 10⁹
λ₁ = 2.50 10⁻² m
f₂ = 18 GHz = 18 10⁹ Hz
λ₂ = 3 10⁸ /18 10⁹
λ₂ = 1.66 10⁻² m
Unfortunately in your exercise the specific frequency is not fired, for significant figures they must be the same number as the figures of the frequency, in general the frequency has 3 or 4 significant figures
Answer:


Explanation:
Knowing that the truck travels up a hill with a 5.4º incline
The horizontal component of the truck's velocity is:

The vertical component of the truck's velocity is:

I don't know I'm just a troll.