So the -4x is the M and then 6 is the B. So m is the slope and B is the y-intercept. The 6 goes on the y axis and the -4 will be how the line looks. It’ll be rise (-4) over run (1).
Perform the indicated operations. Write answer in descending order.
1 answer:
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Answer:
Height of second tower = 17.32m
Step-by-step explanation:
I have attached a diagram depicting the question.
From the diagram, The first tower is depicted by side AEB and the second tower CD.
While d is the distance that separates the two towers and it's given as 15m.
Now, since the angle of depression of the second tower’s base is 60°, then for triangle BAC. Angle C = 60°.
Thus; using trigonometric ratios;
tan 60° = AB/AC.
This gives; AB = d*tan 60°
Similarly, for the triangle BED, BE = d*tan 30°
Since, AE = CD, thus ;
CD = AB − BE
CD = d (tan 60° − tan 30°)
CD = 15(1.7321 − 0.5774)
CD = 15 × 1.1547
CD ≈ 17.32 m.
So, height of second tower = 17.32 m
Answer:
The rate of plane in still air is 834 km/hr and the rate of wind is 80 km/hr.
Step-by-step explanation:
The airplane travels 6032 km in 8 hours against the wind.
So, ........ (1) {Where u is the speed of plane in still air and v is the wind speed}
Again, the airplane travels 7312 km in 8 hours with the wind.
So, ........ (2)
Now, adding equations (1) and (2) we get,
2u = 1668
⇒ u = 834 km per hour.
So, from equation (1), we get
v = u - 754 = 834 - 754 = 80 km per hour.
Therefore, the rate of the plane in still air is 834 km/hr and the rate of wind is 80 km/hr. (Answer)