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2 years ago

12

4) At a store, pears cost $0.74 per pound. How much will 3.5 pounds of pears cost?

1 answer:

erica [24]2 years ago

3 0

Answer:

$2.59

Step-by-step explanation:

.74 per pound

pounds=3.5

.74x3.5=$2.59

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HELP <br>Which equations represent hyperbolas?

MissTica

An elliptical equation is in the form
Ax^2+Bx+Cy^2+Dy+E=0
the equation is a Hyperbola. When x and y are both squared, and exactly one of the coefficients is negative and exactly one of the coefficients is positive.
1-49x^2-98x-64y^2+256y-2831=0
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2 years ago

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Recall the chapter example which described the fact that the mean IQ in large, diverse populations is 100 and the standard devia

vova2212 [387]

Answer:

The margin of error for the 99% confidence level for this sample is ±2.23.

None of the given figures is close to the answer:

E. None of the above

Step-by-step explanation:

margin of error (ME) around the mean can be calculated using the formula

ME= $\frac{z*s}{\sqrt{N} }$ where

z is the corresponding statistic of the 99% confidence level (2.576)

s is the population IQ standard deviation (15)

N is the sample size (300)

Using these numbers we get:

ME= $\frac{2.576*15}{\sqrt{300} }$ ≈ 2.23

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2 years ago

A group of dental researchers are testing the effects of acidic drinks on dental crowns. They have five containers of crowns lab

mestny [16]

Answer:

$\begin{array}{cccccc}{x} & {V} & {W} & {X} & {Y} & {Z} & P(x) & {0.20} & {0.20} & {0.20} & {0.20} & {0.20} \ \end{array}$

Step-by-step explanation:

Given

$S = \{V,W,X,Y,Z\}$

$n(S) = 5$

Required

The probability model

To do this, we simply calculate the probability of each container.

So, we have:

$P(V) = \frac{n(V)}{n(S)} = \frac{1}{5} = 0.20$

$P(W) = \frac{n(W)}{n(S)} = \frac{1}{5} = 0.20$

$P(X) = \frac{n(X)}{n(S)} = \frac{1}{5} = 0.20$

$P(Y) = \frac{n(Y)}{n(S)} = \frac{1}{5} = 0.20$

$P(Z) = \frac{n(Z)}{n(S)} = \frac{1}{5} = 0.20$

So, the probability model is:

$\begin{array}{cccccc}{x} & {V} & {W} & {X} & {Y} & {Z} & P(x) & {0.20} & {0.20} & {0.20} & {0.20} & {0.20} \ \end{array}$

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2 years ago

At the time she had $237 ,the cost of a lesson rose to &19.how many lesson can she pay for with remaining &237

ad-work [718]

12.5, just divide 237 by 19

8 0

2 years ago

Please help I’ll mark you as brainliest if correct!

Pavlova-9 [17]

Answer:

3 ways

36÷6=6

36÷2=18

36÷3=12

maybe if not then 2 or 4

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1 year ago

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