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3 years ago

How to find the answer to 9x3

Mathematics

1 answer:

Contact [7]3 years ago

6 0

Answer:

Step-by-step explanation:

Do it this way: 9*3 is basically 9+9+9 which equals 27, so the answer is 27. You can also draw a picture:

o o o

o o o = 27 dots

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A rocket is launched from a tower. The height of the rocket, y in feet, is related to the time after launch, x in seconds, by th

Alex_Xolod [135]

Answer:

14.52 seconds.

Step-by-step explanation:

We have been given that the height of the rocket, y in feet, is related to the time after launch, x in seconds, by the given equation

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3 years ago

Andre has $ 90 dollars to spend on sneakers. This is 75% of the cost of the sneakers. How much more will the need? Solve and exp

goldenfox [79]

Answer:

I suppose the answer would be 120

Step-by-step explanation:

Well if 90 is 75% then 50% should be 60 and 25% should be 30.

so its going up and down by 30, so that would make 100% 120

please give brainliest

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3 years ago

A coin is thrown 3 times. What is the probability that at least one head is thrown?.

zvonat [6]

Answer:7/8

A coin is tossed 3 times. The probability of getting at least one head is 7/8.

3 0

2 years ago

Read 2 more answers

Which is the simplified form of the expression ((2 Superscript negative 2 Baseline) (3 Superscript 4 Baseline)) Superscript nega

AlekseyPX

Answer:

The option "StartFraction 1 Over 3 Superscript 8" is correct

That is $\frac{1}{3^8}$ is correct answer

Therefore $[(2^{-2})(3^4)]^{-3}\times [(2^{-3})(3^2)]^2=\frac{1}{3^8}$

Step-by-step explanation:

Given expression is ((2 Superscript negative 2 Baseline) (3 Superscript 4 Baseline)) Superscript negative 3 Baseline times ((2 Superscript negative 3 Baseline) (3 squared)) squared

The given expression can be written as

$[(2^{-2})(3^4)]^{-3}\times [(2^{-3})(3^2)]^2$

To find the simplified form of the given expression :

$[(2^{-2})(3^4)]^{-3}\times [(2^{-3})(3^2)]^2$

$=(2^{-2})^{-3}(3^4)^{-3}\times (2^{-3})^2(3^2)^2$ ( using the property $(ab)^m=a^m.b^m$ )

$=(2^6)(3^{-12})\times (2^{-6})(3^4)$ ( using the property $(a^m)^n=a^{mn}$

$=(2^6)(2^{-6})(3^{-12})(3^4)$ ( combining the like powers )

$=2^{6-6}3^{-12+4}$ ( using the property $a^m.a^n=a^{m+n}$ )

$=2^03^{-8}$

$=\frac{1}{3^8}$ ( using the property $a^{-m}=\frac{1}{a^m}$ )

Therefore $[(2^{-2})(3^4)]^{-3}\times [(2^{-3})(3^2)]^2=\frac{1}{3^8}$

Therefore option "StartFraction 1 Over 3 Superscript 8" is correct

That is $\frac{1}{3^8}$ is correct answer

6 0

3 years ago

Read 2 more answers

I’m slow and lazy and yeah sorry just at least help

Anna007 [38]

Answer:

2) x = 6 y = 7 3) x = -5 y= 2

Step-by-step explanation:

2) 10x - 8y = 4

2(-5x + 3y = -9)

-10x + 6y = -18

10x - 8y = 4 Add both equations together

-2y = -14

y = 7 Divide both sides by -2

10(x) - 8(7) = 4 Plug in 7 for the y to solve for x

10x - 56 = 4

+ 56 + 56 Add 56 to both sides

10x = 60

x = 6 Divide both sides by 10

3) Where the two lines intersect, that is the solution to x and y.

The lines intersect at (-5,2). x = -5 y = 2

3 0

3 years ago