From the given condition, it must be seen to it that the width must also be the lowest whole-number possible. Thus, the width should be equal to 1 yard. The given 36 is the perimeter of the run.
P = 2L + 2W
36 = 2L + 2(1)
L = 17
Thus, the longest whole-number length is equal to 17 yards.
Answer:
We know the are of the square is 7x as that squared would =49x^2 making the perimeter 28x so the last side of the triangle has to be 21x-4
legs of the triangles
Each triangle 30-60-90 is:
one leg: 15 ft => short diagonal = 2 * 15ft = 30ft
other leg, x:
tan(30) = 15 / x => x = 15 ft / tan(30) = 25.98 ft
=> long diagonal = 2 * 25.98ft = 51.96 ft
side of the rhoumbus = hypotenuse of one triangle
side of the rhombus = √ [ (15)^2 + (25.98)^2 ] = √(900) = 30 ft
Area of the rhombus:
4 * area of one triangle = 4 [base*height/2] = 4*15*25.98/2 = 779.43 ft^2
The shortest distance accross the garden is equal to the side of the rhombus = 30 ft
two gallons of a light green paint
Answer:
60 slices is the answer
300 mm (30 cm) / 5mm
= 60
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