Can somebody help with this problem?

Mathematics

1 answer:

Anastasy [175]2 years ago

4 0

Answer:

x=-5 or -5

Step-by-step explanation:

x - 4 = 2x + 1

Subtract x from both sides canceling out the x on the left, getting...

-4 = x + 1

Then subtract the 1 from both sides canceling out the 1 on the right, getting...

-5 = x

Subtracting x from 2x gets you 1x which you just write as x because there is only one x. Doing the equation from the other side will still get you the same answer and I will show you.

x - 4 = 2x + 1

-x - 4 = 1

-x = 5

x = -5

Hope this helps!

You might be interested in

PLEASE HELP ME I'M DESPERATE.<br> Delta Math Question!!!

makkiz [27]

Answer:

cos S = $\frac{7}{25}$

Step-by-step explanation:

this is a 7- 24- 25 right angle with RS = 7 , then

cos S = $\frac{adjacent}{hypotenuse}$ = $\frac{RS}{QS}$ = $\frac{7}{25}$

7 0

1 year ago

In a shipment of 56 vials, only 13 do not have hairline cracks. If you randomly select 3 vials from the shipment, in how many wa

Elden [556K]

Answer: 27434

Step-by-step explanation:

Given : Total number of vials = 56

Number of vials that do not have hairline cracks = 13

Then, Number of vials that have hairline cracks =56-13=43

Since , order of selection is not mattering here , so we combinations to find the number of ways.

The number of combinations of m thing r things at a time is given by :-

$^nC_r=\dfrac{n!}{r!(n-r)!}$

Now, the number of ways to select at least one out of 3 vials have a hairline crack will be :-

$^{13}C_2\cdot ^{43}C_{1}+^{13}C_{1}\cdot ^{43}C_{2}+^{13}C_0\cdot ^{43}C_{3}\\\\=\dfrac{13!}{2!(13-2)!}\cdot\dfrac{43!}{1!(42)!}+\dfrac{13!}{1!(12)!}\cdot\dfrac{43!}{2!(41)!}+\dfrac{13!}{0!(13)!}\cdot\dfrac{43!}{3!(40)!}\\\\=\dfrac{13\times12\times11!}{2\times11!}\cdot (43)+(13)\cdot\dfrac{43\times42\times41!}{2\times41!}+(1)\dfrac{43\times42\times41\times40!}{6\times40!}\\\\=3354+11739+12341=27434$