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frosja888 [35]
3 years ago
10

Bacteria are the most common example of exponential growth. Select a number between 2 and 10 to represent the hourly growth rate

of a certain bacteria. For example, selecting the number 8 would mean that the amount of bacteria will be 8 times greater after every hour.
a. Suppose you start with one single bacterium. Make a table of values showing the number of bacteria that will be present after each hour for the first six hours using the hourly growth rate that you selected. Then determine how many bacteria will be present once 24 hours have passed.
b. Explain why this table represents exponential growth.
c. Using this example, explain why any nonzero number raised to a power of zero is equal to one.
d. Write a rule for this table.
e. Suppose you started with 100 bacteria, but they still grew by the same growth factor. How would your rule change? Explain your answer.
Mathematics
2 answers:
shusha [124]3 years ago
4 0

Answer:

bh

Step-by-step explanation:

AysviL [449]3 years ago
4 0

Answer:

Answers are below

Step-by-step explanation:

Hour 0                 1 bacterium

Hour 1                  3 bacterium

Hour 2                 9 bacterium

Hour 3               27 bacterium

Hour 4                81 bacterium

Hour 5            243 bacterium

Hour 6            729 bacterium

After 24 hours, the number of the bacterium will reach 282,429,536,481.

B)  This table represents exponential growth because of the number of bacterium always being multiplied by 3.

C)  The reason that any number to the zero power is one is that any number to the zero power is just the product of no numbers at all, which is the multiplicative identity, 1.

D)  Y = 1 + 3 to the power of x

E)  The rule would change by having all of the numbers multiplied by 100 since there is 100 bacterium at Hour 0.

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Klio2033 [76]
The vertex of the two functions is in the same place, so there is no translation involved. Point (0, 4) on f(x) is point (0, 12) on g(x).

The appropriate choice seems to be ...
    <span>It is stretched vertically by a factor of 3.</span>
5 0
3 years ago
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If f(1) =5 and f(n) = f(n-1)+2, then f(4) =
Vadim26 [7]

Answer:

3.11

Step-by-step explanation:

f(4)=f(4-1)+2

=f(3)+2

=f(3-1)+2+2

=f(2)+4

=f(2-1)+2+4

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5 0
3 years ago
Set up but do not solve for the appropriate particular solution yp for the differential equation y′′+4y=5xcos(2x) using the Meth
taurus [48]

Answer:

So, solution of  the differential equation is

y(t)=-\frac{5x^2}{4}\cot 2x\cdot \cos  2x+c_1e^{-2it}+c_2e^{2it}\\

Step-by-step explanation:

We have the given differential equation: y′′+4y=5xcos(2x)

We use the Method of Undetermined Coefficients.

We first solve the homogeneous differential equation y′′+4y=0.

y''+4y=0\\\\r^2+4=0\\\\r=\pm2i\\\\

It is a homogeneous solution:

y_h(t)=c_1e^{-2i t}+c_2e^{2i t}

Now, we finding a particular solution.

y_p(t)=A5x\cos 2x\\\\y'_p(t)=A5\cos 2x-A10x\sin 2x\\\\y''_p(t)=-A20\sin 2x-A20x\cos 2x\\\\\\\implies y''+4y=5x\cos 2x\\\\-A20\sin 2x-A20x\cos 2x+4\cdot A5x\cos 2x=5x\cos 2x\\\\-A20\sin 2x=5x\cos 2x\\\\A=-\frac{x}{4} \cot 2x\\

we get

y_p(t)=A5\cos 2x\\\\y_p(t)=-\frac{5x^2}{4}\cot 2x\cdot \cos  2x\\\\\\y(t)=y_p(t)+y_h(t)\\\\y(t)=-\frac{5x^2}{4}\cot 2x\cdot \cos  2x+c_1e^{-2it}+c_2e^{2it}\\

So, solution of  the differential equation is

y(t)=-\frac{5x^2}{4}\cot 2x\cdot \cos  2x+c_1e^{-2it}+c_2e^{2it}\\

7 0
3 years ago
Luis bought two pieces of wax to make candles. One piece weighed 3.49 kg, and the other weighed 4.71 kg. If wax costs $1.80 per
EleoNora [17]

(3.49+4.71)1.80=cost

(8.2)1.80=cost

14.76=cost

Luis spends $14.76 all together  


8 0
3 years ago
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Ella would have 65/8ft wire all together.
3 0
3 years ago
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