The relationship between the length & the width of the closet and the length of the wall is an illustration of a linear equation.
- <em>The equation for f(l) is: </em>
<em>.</em> - <em>The desired length and width are 8m and 4m</em>
<em />
Given that:
Divide both sides by 2
<u>Equation of f(l)</u>
The sum of the length and the width is represented as: f(l).
So, we have:
Substitute
See attachment for the graph of f(l)
<u>The desired dimension</u>
From the question, we understand that the total length is 12m.
This means that:
So, we have:
Divide both sides by 1.5
Recall that:
Hence, the desired length and width are 8m and 4m, respectively.
Read more about linear equations at:
brainly.com/question/2263981
As a decimal 4/15 = 0.2666667
As a decimal 3/10 = 0.3 [talk about close]
3/10 is bigger.
You could take an average to find something between 4/15 and 3/10
1/2(4/15 + 2/10)
1/2(8/30 + 6/30)
1/2(14/30)
1/2(7/15)
7/30 is between the two given numbers..
Answer:
B. (-7 +/-√33) / 4
Step-by-step explanation:
2x2 + 7x + 2 = 0
x = [-7 +/- √(7^2 - 4*2*2)] / 2*2
x = -7/4 +/- √(33) / 4
= (-7 +/-√33) / 4
Answer:
Statement 2 (The ages of the Stars are the most dispersed from the team’s mean).
Step-by-step explanation:
Standard deviation is one way to measure the average of the data by determining the spread of the data. It actually explains how much the observation points are further away from the mean of the data. Higher the standard deviation, higher the spread of the data and higher is the uncertainty. This means that the team with the highest standard deviation will have the most dispersion. In this case, the standard deviation of 4.1 is the largest number, therefore, the statement "The ages of the Stars are the most dispersed from the team’s mean." is true i.e. the option 2!!!
