Answer:
A) 68.33%
B) (234, 298)
Step-by-step explanation:
We have that the mean is 266 days (m) and the standard deviation is 16 days (sd), so we are asked:
A. P (250 x < 282)
P ((x1 - m) / sd < x < (x2 - m) / sd)
P ((250 - 266) / 16 < x < (282 - 266) / 16)
P (- 1 < z < 1)
P (z < 1) - P (-1 < z)
If we look in the normal distribution table we have to:
P (-1 < z) = 0.1587
P (z < 1) = 0.8413
replacing
0.8413 - 0.1587 = 0.6833
The percentage of pregnancies last between 250 and 282 days is 68.33%
B. We apply the experimental formula of 68-95-99.7
For middle 95% it is:
(m - 2 * sd, m + 2 * sd)
Thus,
m - 2 * sd <x <m + 2 * sd
we replace
266 - 2 * 16 <x <266 + 2 * 16
234 <x <298
That is, the interval would be (234, 298)
Answer:
y ≈ 5.2
Step-by-step explanation:
∠ F = 180° - (42 + 48)° ← sum of angles in a triangle
∠ F = 180° - 90° = 90°
Thus Δ DEF is right at F
Using the sine ratio in the right triangle
sin48° =
=
=
( multiply both sides by 7 )
7 × sin48° = y , then
y ≈ 5.2 ( to the nearest tenth )
Answer:
x = 6
Step-by-step explanation:
the tangent- tangent angle UVW is half the difference of the intercepted arcs, that is
∠ UVW =
(UW - WU ) , then
5x + 17 =
(37x + 5 - (23x - 5) ) ← multiply both sides by 2
10x + 34 = 37x + 5 - 23x + 5
10x + 34 = 14x + 10 ( subtract 14x from both sides )
- 4x + 34 = 10 ( subtract 34 from both sides )
- 4x = - 24 ( divide both sides by - 4 )
x = 6
I don't know if this is what your looking for but 113% = 113/100 can be 1 13/100.