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qwelly [4]
3 years ago
10

A famous chemical company in Oman hired you as a research chemist. On the very first day of your job, your senior

Chemistry
1 answer:
Mariulka [41]3 years ago
7 0

Answer:

D. 3.699 g/mL

Explanation:

Density of liquid X = 3.0771

Percentage composition of X in the mixture = 32.77% = 0.3277

Density of liquid Y = 4.0017

Percentage composition of Y in the mixture = 67.23% = 0.6723

Density of mixture of X and Y = (density of X × percentage composition of X) + (density of Y × percentage composition of Y)

Density of mixture of X and Y = (3.0771 × 0.3277) + (4.0017 × 0.6723)

Density of mixture of X and Y = 1.0084 + 2.6903

Density of mixture of X and Y = 3.6987 g/mL

When the metal of unknown density is dropped into a mixture of X and Y, it is suspended in the mixture. This is because it has a density equal to that of the mixture.

Therefore, the density of the unknown metal is 3.6987 g/mL which is approximately 3.699 g/mL to three decimal places.

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