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3 years ago

Neeed heellllpppppppp please

Chemistry

2 answers:

Cloud [144]3 years ago

7 0

Answer: A- Potassium (K)

Ratling [72]3 years ago

5 0

Answer

A

Step by step explanation

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How many grams of potassium iodine, kl,must be added to 500.0 grams of water to produce a 6.00% solution ?

GuDViN [60]

Answer:

grams KI needed = 31.9 grams

Explanation:

? g KI + 500 g water => 6.0% KI solution

let x = grams KI needed.

Percent = part/total x 100% = (x/x+500)·100% = 6.0%

Solve for 'x' ...

x / x + 500 = 6/100 = 0.06 => x = 0.06(x + 500) => x = 0.06x + 30

x - 0.06x = 30 => 0.94x = 30 => x = 30/0.94 = 31.9 gms KI needed.

6 0

3 years ago

Help me Benjamin please

pogonyaev

Answer:

1...option B

2... peroids

3..group

4.. metals

5...7

6...dmitri mendeleev

7.. xenon

8... compound can be broken down by physical means

9... they can be broken down into simpler substance

sry if its wrong

last two 8th and 9th i do t think ots correct

4 0

3 years ago

Read 2 more answers

Bromine is is reddish-brown liquid that boils at 59 degrees. bromine is highly reactive with many metals, for example, it reacts

katrin2010 [14]

A physical property of an element is a property of an element that can observed or measured without changing the chemical nature of the element.

A chemical property of an element is a property of an element that can only be observed or measure when the chemical property of the element is altered or changed.

Based on this;
The boiling point of bromine is a physical property of bromine.
The high reactivity of bromine with many elements is a chemical property of bromine.

4 0

3 years ago

Write the molecular, ionic, and net ionic equations for the reaction of a: hcl with koh, b: hcho2 with lioh and c: n2h4 with hcl

igor_vitrenko [27]

Answer:

Here's what I get.

Explanation:

a. HCl + KOH

$\rm Molecular: KOH(aq)+ HCl(aq) \longrightarrow \, KCl(aq) + H_{2}O(l)\\\rm Ionic: K^{+}(aq) + OH^{-}(aq)+ H^{+}(aq) + Cl^{-}(aq) \longrightarrow \, K^{+}(aq)+ Cl^{-}(aq) + H_{2}O(l)\\\rm Net ionic: OH^{-}(aq)+ H^{+}(aq) \longrightarrow \, H_{2}O(l)\\$

b. HCHO₂ + LiOH

Only the first H in HCHO₂ is acidic

$\rm Molecular: HCHO_{2}(aq)+ LiOH(aq) \longrightarrow \, LiCHO_{2}(aq) + H_{2}O(l)\\\rm Ionic: HCHO_{2}(aq) + Li^{+}(aq) + OH^{-}(aq) \longrightarrow \, Li^{+}(aq)+ CHO_{2}^{-}(aq) + H_{2}O(l)\\\rm Net ionic: HCHO_{2}(aq) + OH^{-}(aq) \longrightarrow \, CHO_{2}^{-}(aq) + H_{2}O(l)\\$

c. N₂H₄ + HCl

Both N atoms in N₂H₄ are basic, so the compound reacts with 2 mol of HCl.

$\rm Molecular: N_{2}H_{4}(aq)+ 2HCl(aq) \longrightarrow \, N_{2}H_{6}Cl_{2}(aq) \\\rm Ionic: \qquad N_{2}H_{4} (aq) + 2H^{+}(aq) + 2Cl^{-}(aq) \longrightarrow \, N_{2}H_{6}^{+}(aq) + 2Cl^{-}(aq)\\\rm Net ionic: \ N_{2}H_{4} (aq) + 2H^{+}(aq) \longrightarrow \, N_{2}H_{6}^{+}(aq)\\$

6 0

4 years ago

What is the molecular formula of a compound whose molar mass is 112 and whose empirical formula is ?

enot [183]

Well I need to know the empirical formula, molecular formula.
Then I can multiply the grams of each individual element by their molar mass, and divide the smallest element by itself, and the other elements by the smallest element. Then I get the empirical formula

7 0

3 years ago