You need 158.70 grams of Fe2O3 to produce 111 grams of Fe. This is calculated by using the molar masses and stoichiometric relationship of the two compounds.
Solution:
MM Fe = 55.845 g/mol
MM Fe2O3 = 159.69 g/mol
Fe: Fe2O3 = 2 mol:1 mol
11 g FE (1 mol Fe/55.845 g Fe) (1 mol Fe2O3/2 mol Fe) (159.69 g Fe2O3 / 1 mole Fe2O3) = 158.70 grams Fe2O3
Answer:
<h2>3.31 g/mL</h2>
Explanation:
The density of a substance can be found by using the formula

From the question
mass = 23.2 g
volume = final volume of water - initial volume of water
volume = 62 - 55 = 7 mL
We have

We have the final answer as
<h3>3.31 g/mL</h3>
Hope this helps you
Answer:
will be 90054 J
Explanation:
Number of moles = (mass)/(molar mass)
Molar mass of
= 134.45 g/mol
So, 1.00 g of
=
of
= 0.00744 mol of 
0.00744 mol of
produces 670 J of heat
So, 1 mol of
produces
of heat or 90054 J of heat