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irga5000 [103]
3 years ago
14

Helppppppp. much needed help lol

Chemistry
2 answers:
Korolek [52]3 years ago
8 0
Isotope is the correct answer
Olenka [21]3 years ago
3 0

Answer:

Isotope

Explanation:

Isotopes are variants of a particular chemical element which differ in neutron number, and consequently in nucleon number.

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96 K = _____ -177°C 0°C 96°C 369°C
velikii [3]
ºC = K - 273

ºC = 96 - 273

= -177ºC

answer A

hope this helps!
6 0
3 years ago
Read 2 more answers
What does it mean to say an equation is balanced? Why is it important for an equation to be balanced?​
Rom4ik [11]

Answer: It is important for an equation to be balanced because if it is not then the reactants won't match the products.

Explanation: I don't know if you will understand this but here:

Let's say you're cooking eggs, you're reactants so to speak would be 3 eggs and 1 tablespoon of oil so you put it together using heat and a pan. Your products have to match what you have in the beginning. You cannot have an equation that looks like this

Reactants = 3eggs + 1Tbsp oil ---pan/heat---> 6eggs + 1 cup of oil

You cannot get something from what you don't have. The number of how much of an element you have must be the same of both sides of the equation.

8 0
1 year ago
Determine the mass in grams of sucrose that must be added to 26 g of water to make a 1.15 m solution. Enter your answer to 2 dec
True [87]

Answer:

10.23 grams of sucrose should be added.

Explanation:

1.15 m means molality (moles of solute in 1kg of solvent)

1.15 moles of sucrose are contained in 1 kg of solvent (1000 g)

Let's determine the moles in our mass of solvent.

Firstly we convert the g to kg → 26 g . 1kg/1000g = 0.026 kg

m . mass (kg) =  1.15 mol/kg . 0.026kg → 0.0299 moles.

Finally we convert the moles to mass (mol . molar mass)

0.0299 mol . 342.3 g/mol = 10.23 g

4 0
3 years ago
Read 2 more answers
On x
Lena [83]

Answer:

2

Explanation:

1+1=2

6 0
2 years ago
What does converse mean
Xelga [282]

Answer:

engage in conversation.

Explanation:

8 0
3 years ago
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