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spayn [35]
3 years ago
13

Which answer provides the correct name for the following hydrocarbon?

Chemistry
2 answers:
motikmotik3 years ago
7 0

Answer: Option (b) is the correct answer.

Explanation:

In the given molecule, there are five carbon atoms attached linearly to each other will single bonds only.

So, it is known that when a compound contains only carbon and hydrogen atoms attached  single bondedly to each other then this type of hydrocarbon is known as alkane.

Their general formula is C_{n}H_{2n+2}, where n is the number of carbon atoms present. Suffine "ane" is added to the name of alkane.

Thus, we can conclude that name of the given hydrocarbon is pentane.

ivanzaharov [21]3 years ago
4 0
1) Hydrocarbon: CH3 - CH2 - CH2 - CH2 - CH3

2) Only single bonds => alkane => sufix ane

3) no substitutions

4) 5 carbons = > prefix penta.

Therefore, the name is pentane.
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The box shows the element nitrogen as it appears in the periodic table.
Helen [10]

Answer:

I am 90% sure it is A - if I am wrong please let me know so I can fix my mistakes and improve

Explanation:

6 0
3 years ago
An atom of sodium -23 has a net charge of +1 identify the number of protons, neutrons, and electrons in the atom. Then explain h
nikitadnepr [17]

Number of protons is 11

Number of neutrons is 12

Number of electrons is 10

For a neutral Na, Sodium atom:

The mass number P+N = 23

Atomic number (E or P) = 11

A charged Na atom that has lost an electron is positively charged and so:  Number of Protons = 11 (Still the same)

Number of neutrons = 12

Number of electrons = 11-1=10 (the atom has lost an electron)

If an atom loses electron, it becomes positively charged ie. P>E

Learn more about Electrons, Protons, Neutrons here:

brainly.com/question/13131235

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6 0
1 year ago
How many numbers between 1-100 are equal to five times an odd number?​
VashaNatasha [74]

<u>Answer:</u>

<em>There are 10 numbers between 1-100 which are equal to 5 times an odd number.</em>

<u>Explanation:</u>

<em>The odd numbers between 1 and 100 are 1,3,5,7….. </em>

When these when these odd numbers are multiplied by 5 we get the following result.

5 \times 1=5

5 \times 3=15

5 \times 19=95

<em>These products form an AP 5,15,25,…..,95 </em>

common difference d=10

first term a=5  

last term a_n=95  

we have to calculate the number of terms n

The expression for last term a_n of an AP is  

<em>a_n=a+(n-1)d</em>

<em>a_n=a+nd-d</em>

<em>nd=a_n-a+d =95-5+10=100 </em>

<em>n= \frac{100}{d}= \frac{100}{10}=10</em>

4 0
3 years ago
Which of the following conditions will result in a reaction that is spontaneous only at high temperatures?
Korolek [52]
You have to use the equation ΔG=ΔH-TΔS.
With that equation you know that a reaction with a positive change in enthalpy and positive change in entropy will only be spontaneous at high temperatures since ΔG needs to be negative for a reaction to be spontaneous.

I hopet this helps.  Let me know if anything is unclear.
6 0
3 years ago
A compound that is composed of only carbon and hydrogen contains 80.0% c and 20.0% h by mass. What is the empirical formula of t
gladu [14]

<u>Solution</u> : Emperical Formula =  CH_{3}

Emperical Formula - A formula that gives the simplest whole number ratio of atom in a compound.

In the question percentages are given then assume that the total mass is 100grams so that the mass of each element is equal to the percentage given.

Given : 80.0g Carbon

            20.0g Hydrogen

First convert the given masses into moles.

80.0g\text{ C} \times \frac{1 g/mole \text{ C}}{12.0 g/mole \text{ C}}= 6.66\text{mole of C}

20.0g\text{ H} \times \frac{1 g/mole \text{ H}}{1 g/mole \text{ H}}= 20.0\text{mole of H}

Value of each mole divided by the smallest number of moles and then round off.

Moles ratio of the element are

\frac{6.66}{6.66}\text{mole of C}= 1

\frac{20.0}{6.66}\text{mole of C}= 3

This is the mole ratio of the elements and is repersented by the subscript in the emperical formula.

Emperical Formula =  CH_{3}

3 0
3 years ago
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