Answer:
a.The phenotypic proportions obtained after having the genotypes are 50% marbled seeds, 25% spotted and dotted seeds since they are codominant, 25% spotted seeds.
b. Taking into account the F1 genotypes in the previous point, the expected phenotypes for the first crossing are 100% marbled seeds and for the second crossing 100% dotted seeds.
Explanation:
Let's suppose:
Marbled allele: M
Spotted allele: S
Dotted allele: D
Allele for Clear: C
a. Because both crosses were between homozygous parents, the entire F1 genotype is the same.
For the first crossing the descendants have the MS genotype, and for the second crossing the descendants have the DC genotype. It is enough to make a Punnett square to obtain the different combinations of genotypes between the crossing of MS and DC.
In what organisms are you referring to?
Options are not provided in the question. I found the answer on the Internet.
Yes, deletion of the possible control elements can cause reduction in reporter gene expression. Due to deletion of a control element, the activator cannot bind to the enhancer. This causes reduction in the gene expression.
Answer: Deletion of element no. 3 causes a reduction in reporter gene expression.
