3 years ago

Work out the point of intersection of the lines 2x + 3y = 11 and 2y = 13 – 3x

Mathematics

1 answer:

borishaifa [10]3 years ago

3 0

Answer:

x = 3.4

y = 1.4

Step-by-step explanation:

2x + 3y = 11

2y = 13 – 3x, then y = (13 - 3x)/2

substitute for y:

2x + 3((13 - 3x)/2) = 11

reduce:

2x + (39 - 9x)/2 = 11

reduce:

2x + 19.5 - 4.5x = 11

subtract 19.5 from both sides of the equation and combine for x:

-2.5x = -8.5

divide both sides by -2.5:

x = 3.4

y = (13 - 3(3.4))/2 = (13 - 10.2)2 = 1.4

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Answer:

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$(-2,-1)$

General Formulas and Concepts:

Order of Operations: BPEMDAS
Distance Formula: $d = \sqrt{(x_2-x_1)^2+(y_2-y_1)^2}$
Midpoint Formula: $(\frac{x_1+x_2}{2},\frac{y_1+y_2}{2})$

Step-by-step explanation:

Step 1: Define

(5, -1)

(-9, -1)

Step 2: Find distance d

Substitute: $d = \sqrt{(-9-5)^2+(-1-(-1))^2}$
Simplify: $d = \sqrt{(-9-5)^2+(-1+1)^2}$
Subtract/Add: $d = \sqrt{(-14)^2+(0)^2}$
Evaluate: $d = \sqrt{196}$
Evaluate: $d = \14$

Step 3: Find Midpoint

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Subtract: $(\frac{-4}{2},\frac{-2}{2})$
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2 years ago

Read 2 more answers